Question
A large tank filled with water to a height 'h' is to be emptied through a small hole at the bottom. The ratio of time taken for the level of water to fall from h to h/2 and from h/2 to zero is
Answer: Option C
:
C
Time taken for the level to fall from H to H' t=AA0√2g[√H−√H′]
According to problem - the time taken for the level to fall from h to h2 t1=AA0√2g[√h−√h2]
and similarly time taken for the level to fall from h2 to zero t2=AA0√2g[√h2−0]∴t1t2=1−1√21√2−0=√2−1
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:
C
Time taken for the level to fall from H to H' t=AA0√2g[√H−√H′]
According to problem - the time taken for the level to fall from h to h2 t1=AA0√2g[√h−√h2]
and similarly time taken for the level to fall from h2 to zero t2=AA0√2g[√h2−0]∴t1t2=1−1√21√2−0=√2−1
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