Question
A manometer connected to a closed tap reads 3.5 × 105 N/m2. When the valve is opened, the reading of manometer falls to 3.0 × 105 N/m2, then velocity of flow of water is
Answer: Option B
:
B
Bernoulli's theorem for unit mass of liquid
Pρ+12v2 = constant
As the liquid starts flowing, it pressure energy decreases 12v2=P1−p2ρ⇒12v2=3.5×105−3×105103
⇒v2=2×0.5×105103⇒v2=100⇒v=10m/s
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:
B
Bernoulli's theorem for unit mass of liquid
Pρ+12v2 = constant
As the liquid starts flowing, it pressure energy decreases 12v2=P1−p2ρ⇒12v2=3.5×105−3×105103
⇒v2=2×0.5×105103⇒v2=100⇒v=10m/s
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