Question
A jogger running at 9 kmph alongside a railway track in 240 metres ahead of the engine of a 120 metres long train running at 45 kmph in the same direction. In how much time will the train pass the jogger?
Answer: Option C
$$\eqalign{
& {\text{Speed}}\,{\text{of}}\,{\text{train}}\,{\text{relative}}\,{\text{to}}\,{\text{jogger}} \cr
& = \left( {45 - 9} \right)\,{\text{km/hr}} \cr
& = 36\,{\text{km/hr}} \cr
& {36 \times \frac{5}{{18}}} \,{\text{m/sec}} \cr
& = 10\,{\text{m/sec}} \cr
& {\text{Distance}}\,{\text{to}}\,{\text{be}}\,{\text{covered}} \cr
& = \left( {240 + 120} \right)\,m \cr
& = 360\,m \cr
& \therefore {\text{Time}}\,{\text{taken}} \cr
& = {\frac{{360}}{{10}}} \,{\text{sec}} \cr
& = 36\,{\text{sec}} \cr} $$
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$$\eqalign{
& {\text{Speed}}\,{\text{of}}\,{\text{train}}\,{\text{relative}}\,{\text{to}}\,{\text{jogger}} \cr
& = \left( {45 - 9} \right)\,{\text{km/hr}} \cr
& = 36\,{\text{km/hr}} \cr
& {36 \times \frac{5}{{18}}} \,{\text{m/sec}} \cr
& = 10\,{\text{m/sec}} \cr
& {\text{Distance}}\,{\text{to}}\,{\text{be}}\,{\text{covered}} \cr
& = \left( {240 + 120} \right)\,m \cr
& = 360\,m \cr
& \therefore {\text{Time}}\,{\text{taken}} \cr
& = {\frac{{360}}{{10}}} \,{\text{sec}} \cr
& = 36\,{\text{sec}} \cr} $$
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