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Question
A function f such that f(a)=f′′(a)=......f2n(a)=0 and f has a local maximum value b at x = a, if f (x) is
Options:
A .  (x−a)2n+2
B .  b−1−(x+1−a)2n+1
C .  b−(x−a)2n+2
D .  (x−a)2n+2−b.
Answer: Option C
:
C
For local maximum or local minimum odd derivative must be equal to zero.
For local maxima, even derivative must be negative.
Since maximum value at x = a is b.

f(x)=b(xa)2n+2(f2n+2(a)=ve)
Hence (c) is the correct answer.

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