Question
A fortune teller has numbers from 1-7 in his box. He draws 3 numbers from it. What is the probability that the number picked is of alternate order as odd-even-odd or even-odd-even?
Answer: Option B
:
B
Sample Space: 7×6×5=210
odd-even-odd= 4×3×3=36
even-odd-even= 3×4×2=24
Total ways: 60
P(E)= 60210=27
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:
B
Sample Space: 7×6×5=210
odd-even-odd= 4×3×3=36
even-odd-even= 3×4×2=24
Total ways: 60
P(E)= 60210=27
Was this answer helpful ?
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