- A dog takes 3 leaps for every 5 leaps of a hare. lf one leap of the dog is equal to 3 leaps of the hare, the ratio of the speed of the dog to that of the hare is
The ratio of speed of the dog to that of the hare is the ratio of distances covered by them in the same amount of time.
Let us assume that speed of the Hare is x units/sec
Then speed of the Dog = (3/5)x units/sec
Now, let us assume that the Hare takes n leaps in t seconds
Then, the Dog takes (3/5)n leaps in t seconds
Therefore, the ratio of the distance covered by the Hare to that of the Dog is
Distance covered by the Hare : Distance covered by the Dog
= (n * x * t) : ( (3/5) * n * (3/5)x *t )
= (n * x * t) : ( (9/25) * n * x *t )
= (25/9) : 1
Therefore, the ratio of the speed of the Hare to that of the Dog is
Speed of the Hare : Speed of the Dog
= (25/9) : 1
= 9 : 5
Therefore, the correct answer is Option D: 9:5
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Then the speed of the cat in one unit time =3*3=9
Also the speed of hare =1*5=5
The requireed ratio =9:5
Distance ratio of dog and hare is 3:1,
Now speed =distance/time
S= 3/5 : 1/3
S=3*3 : 1*5
S=9 : 5