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  1. A dog takes 3 leaps for every 5 leaps of a hare. lf one leap of the dog is equal to 3 leaps of the hare, the ratio of the speed of the dog to that of the hare is

Options:
A .  5 : 8
B .  8 : 5
C .  5 : 9
D .  9 ; 5
Answer: Option D

The ratio of speed of the dog to that of the hare is the ratio of distances covered by them in the same amount of time.

Let us assume that speed of the Hare is x units/sec

Then speed of the Dog = (3/5)x units/sec

Now, let us assume that the Hare takes n leaps in t seconds

Then, the Dog takes (3/5)n leaps in t seconds

Therefore, the ratio of the distance covered by the Hare to that of the Dog is

Distance covered by the Hare : Distance covered by the Dog

= (n * x * t) : ( (3/5) * n * (3/5)x *t )

= (n * x * t) : ( (9/25) * n * x *t )

= (25/9) : 1

Therefore, the ratio of the speed of the Hare to that of the Dog is

Speed of the Hare : Speed of the Dog

= (25/9) : 1

= 9 : 5

Therefore, the correct answer is Option D: 9:5

If you think the solution is wrong then please provide your own solution below in the comments section .


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3 Comments

Assume that one dog leap is equal to 3 leaps and one hare leap is equal to 1leap
Then the speed of the cat in one unit time =3*3=9
Also the speed of hare =1*5=5
The requireed ratio =9:5
Time's ratio of dog and hare is 5:3,
Distance ratio of dog and hare is 3:1,
Now speed =distance/time
S= 3/5 : 1/3
S=3*3 : 1*5
S=9 : 5
Please give me a solution

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