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Question

A cistern 6m long and 4 m wide contains water up to a depth of 1 m 25 cm. The total area of the wet surface is:

Options:
A .  49 m2
B .  50 m2
C .  53.5 m2
D .  55 m2
Answer: Option A

Area of the wet surface  = [2(lb + bh + lh) - lb]


= 2(bh + lh) + lb


= [2 (4 x 1.25 + 6 x 1.25) + 6 x 4] m2


= 49 m2


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