**INDUSTRY AND COMPANY AWARENESS (ICA)**

A large cube is formed from the material obtained by melting three smaller cubes of 3, 4 and 5 cm side. What is the ratio of the total surface areas of the smaller cubes and the large cube?

**Answer: Option C**

Volume of the large cube = (3^{3} + 4^{3} + 5^{3}) = 216 cm^{3}.

Let the edge of the large cube be a.

Let the edge of the large cube be a.

So, a^{3} = 216 \(\Rightarrow\) a = 6 cm.

So, Required ratio = \(\left(\frac{6\times(3^{2}\times4^{2}\times5^{2})}{6\times6^{2}}\right)=\frac{50}{36}= 25:18.\)

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