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Question
A block of mass 10 kg slides with velocity of 10 m/s on a rough horizontal surface. It comes to rest after covering a distance of 50 meters. Find the frictional force. 
Options:
A .  1N                    
B .  10N
C .  100N
D .  5N
Answer: Option B
:
B
u = 10m/s
v = 0
s = 50
v2- u2= 2as
a = -1 m/ s2
Friction from is providing this deceleration of the block
A Block Of Mass 10 Kg Slides With Velocity Of 10 M/s On A Ro...
fr = ma
fr = 10 ×1
fr = 10N
so friction is 10N in backward direction.

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