A block is sliding down on an inclined plane. The velocity changes at a constan

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A block is sliding down on an inclined plane. The velocity changes at a constant rate from $10 c m s^{- 1}$ to $15 c m s^{- 1}$ in $2$ seconds. What is its acceleration?

Options:

A .

2.5 c m s^{- 2}

B .

1.5 c m s^{- 2}

C .

4.5 c m s^{- 2}

D .

1.25 c m s^{- 2}

Answer: Option A
:
A

The motion is depicted below

Let $u$ be the initial velocity, $v$ be the final velocity and $t$ be the time taken.
$v = 15 c m s^{- 1}, u = 10 c m s^{- 1}, t = 2 s$
We know that acceleration, $a$ is given by:
$a = \frac{v - u}{t}$
$a = \frac{15 - 10}{2}$ $c m s^{- 2}$
$a = 2.5 c m s^{- 2}$

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