Question
A ball P of mass 2 kg undergoes an elastic collision with another ball Q initially kept at rest. After the collision, ball P continues to move in its original direction with a speed one-fourth of its original speed. What is the mass of ball Q?
Answer: Option B
:
B
Since the collision is elastic, both momentum and kinetic energy are conserved. If m is mass of ball Qand v’ its speed after the collision, the law of conservation of momentum gives
2v=2×v4+mv′
Where v is the original speed of ball P. thus
mv′=3v2orv′=3v2m (i)
The law of conservation of energy gives
12×2×v2=12×2×(v4)2+12mv′2
or mv′2=15v28 (ii)
Using (i) in (ii) we get m = 1.2 kg. Hence the correct choice is (b).
Was this answer helpful ?
:
B
Since the collision is elastic, both momentum and kinetic energy are conserved. If m is mass of ball Qand v’ its speed after the collision, the law of conservation of momentum gives
2v=2×v4+mv′
Where v is the original speed of ball P. thus
mv′=3v2orv′=3v2m (i)
The law of conservation of energy gives
12×2×v2=12×2×(v4)2+12mv′2
or mv′2=15v28 (ii)
Using (i) in (ii) we get m = 1.2 kg. Hence the correct choice is (b).
Was this answer helpful ?
Submit Solution