Question
A body of mass 5 kg is moving along the x-axis with a velocity 2ms−1. Another body of mass 10 kg is moving along the y-axis with a velocity √3ms−1. If they collide at the origin and stick together, then the final velocity of the combined mass is
Answer: Option C
:
C
Momentum of 5 kg mass (p1)=5×2=10kgms−1along the x-axis. Momentum of 10 kg mass (p2)=10√3kgms−1 along the y-axis. These two momenta are perpendicular to each other.
Therefore, the resultant initial momentum is
P=√p21+p22=√(10)2+(10√3)2=20kgms−1
If v ms−1is the velocity of the combined mass, then the final momentum = (10 + 5) v = 15 v kg ms−1
Now, from the principle of conservation of momentum, we have 15 v = 20 or v=43ms−1, which is choice (c).
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:
C
Momentum of 5 kg mass (p1)=5×2=10kgms−1along the x-axis. Momentum of 10 kg mass (p2)=10√3kgms−1 along the y-axis. These two momenta are perpendicular to each other.
Therefore, the resultant initial momentum is
P=√p21+p22=√(10)2+(10√3)2=20kgms−1
If v ms−1is the velocity of the combined mass, then the final momentum = (10 + 5) v = 15 v kg ms−1
Now, from the principle of conservation of momentum, we have 15 v = 20 or v=43ms−1, which is choice (c).
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