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A 1.8 m tall man is standing at some distance from a building. The angle of elevation from his eyes to the top of the building increases from 30 to 60 as he walks 20 m towards the building. Find the height of the building (in m).


Options:
A .   10 m
B .   203 m
C .   20 m
D .   (103 + 1.8) m
Answer: Option D
:
D

A 1.8 M Tall Man Is Standing At Some Distance From A Buildin...
The situation can be represented by the figure above.
tan(ACB)=ABBCBC=ABtan60.....(1)tan(ADB)=ABBDtan30=ABBC+CDBC+CD=ABtan30.....(2) on subtracting equation(1) from (2)CD=ABtan30ABtan60AB=103
Hence, the height of the building is
= AB + BG = (103+1.8)m.



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