A tower is 100 √ 3 m high. Find the angle of elevation of its top from a point 100 m away from its foot. Options: A . &nbsp 30 ∘ B . &nbsp 60 ∘ C . &nbsp 45 ∘ D . &nbsp 15 ∘

Answer: Option B : B Let the angle of elevation be θ . ⇒ t a n θ = P e r p e n d i c u l a r B a s e ⇒ t a n θ = 100 √ 3 100 = √ 3 Therefore, θ = 60 ∘

A tower is 100√3 m high. Find the angle of elevation of its top from a point

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