Question
50 ml of 1 M oxalic acid is shaken with 0.5 gm of wood charcoal. The final concentration of the solution after adsorption is 0.2 M. Amount of oxalic acid absorbed per gm of charcoal is (Use molar mass of hydrated oxalic acid = 126)
Answer: Option C
:
C
Initially weight of oxalic acid present = W=126×1×501000=6.3gm
Finally weight of oxalic acid remaining = W=126×0.2×501000=6.35gm
0.5 gm of charcoal adsorbed 6.3×(1−15)=6.3×(45) gm of oxalic acid
So, amount of oxalic acid adsorbed per gram of charcoal =2×(6.3×(45))=10.08 gm
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:
C
Initially weight of oxalic acid present = W=126×1×501000=6.3gm
Finally weight of oxalic acid remaining = W=126×0.2×501000=6.35gm
0.5 gm of charcoal adsorbed 6.3×(1−15)=6.3×(45) gm of oxalic acid
So, amount of oxalic acid adsorbed per gram of charcoal =2×(6.3×(45))=10.08 gm
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