- 5% people of a village in Sri Lanka died by bombardment, 15% of the remainder left the village on account of fear. If now the population is reduced to 3553, how much was it in the beginning?
Let the initial population of the village be x.
Now, 5% of x = (5/100)*x = (x/20) people died due to bombardment.
So, (x - (x/20)) = (95/100)*x = 0.95x people are remaining in the village after the bombardment.
15% of 0.95x = (15/100)*(0.95x) = (0.15x) people left the village due to fear.
So, (0.95x - 0.15x) = (0.8x) people are remaining in the village after the bombardment and fear.
We know, (0.8x) = 3553 (given)
Therefore, 0.8x = 3553
⇒ x = (3553/0.8)
⇒ x = 4416.25
Hence, the initial population of the village = 4416.25
Rounding off,
Initial population of the village = 4400
Therefore, option D is the correct answer.
Explanation:
Population: Population refers to the total number of people inhabiting a particular place or area at a given time.
Bombardment: Bombardment refers to an action in which a place or an area is attacked with bombs or firearms.
Percentage: Percentage refers to a fraction or ratio expressed as a part of 100. It is denoted by the symbol ‘%’.
Formula:
Let the initial population of the village be x
Then, 5% of x = (5/100)*x = (x/20)
15% of 0.95x = (15/100)*(0.95x) = (0.15x)
So, (0.8x) = 3553
Therefore, 0.8x = 3553
⇒ x = (3553/0.8)
⇒ x = 4416.25
Rounding off,
Initial population of the village = 4400
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X = 4400