Question
If the mean of the set of number x1,x2...xn is ¯x ,then the mean of the number xi+2i,1≤≤n is
Answer: Option B
:
B
¯x=∑ni=1xin⇒∑ni=1xi=n¯x∴∑ni(xi+2i)n=∑ni=1xi+2(1+2+...+n)n=n¯x+2n(n+1)2n=¯x+(n+1)
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:
B
¯x=∑ni=1xin⇒∑ni=1xi=n¯x∴∑ni(xi+2i)n=∑ni=1xi+2(1+2+...+n)n=n¯x+2n(n+1)2n=¯x+(n+1)
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