Question
(sec A+tan A−1)(sec A−tan A+1)tan A=
Answer: Option D
:
D
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:
D
(sec A+tan A−1)(sec A−tan A+1)tan A
=[sec A+(tan A−1)] [sec A−(tan A−1)]tan A
=sec2 A−(tan A−1)2tan A
=sec2 A−(tan2 A−2 tan A+1)tan A
=sec2 A−tan2 A+2 tan A−1tan A
=1+2 tan A−1tan A……(∵1+tan2 A=sec2 A)
=2 tan Atan A
=2
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