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Question


tan2 θ(sec θ1)2=


Options:
A .   1+sin θ1sin θ
B .   1
C .   tan θ
D .   1+cos θ1cos θ
Answer: Option D
:
D

tan2 θ(sec θ1)2=sec2 θ1(sec θ1)2


=(sec θ1)(sec θ+1)(sec θ1)(sec θ1)


=1cos θ+11cos θ1


=1+cos θcos θ1cos θcos θ


=1+cos θ1cos θ



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