Question
Answer: Option A
:
A
Extend OP.Then, atriangle PQT will be formed;where T is the point at which OP cuts QR.
Now,
∠OPQ +∠QPT = 180∘
⇒∠QPT = 180∘-110∘= 70∘
Now, since if OP || RS, ∠SRQ and ∠UTQ are corresponding angles hence, ∠UTQ =∠SRQ = 130∘
Therefore we have,
∠UTQ +∠PTQ = 180∘
⇒∠PTQ = 180∘ - 130∘ = 50∘
In triangle PTQ,
∠PTQ +∠TQP +∠QPT = 180∘
⇒50∘+∠TQP +70∘= 180∘
⇒∠TQP = 180∘- 120∘= 60∘
⇒∠TQP =∠PQR = 60∘
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:
A
Extend OP.Then, atriangle PQT will be formed;where T is the point at which OP cuts QR.
Now,
∠OPQ +∠QPT = 180∘
⇒∠QPT = 180∘-110∘= 70∘
Now, since if OP || RS, ∠SRQ and ∠UTQ are corresponding angles hence, ∠UTQ =∠SRQ = 130∘
Therefore we have,
∠UTQ +∠PTQ = 180∘
⇒∠PTQ = 180∘ - 130∘ = 50∘
In triangle PTQ,
∠PTQ +∠TQP +∠QPT = 180∘
⇒50∘+∠TQP +70∘= 180∘
⇒∠TQP = 180∘- 120∘= 60∘
⇒∠TQP =∠PQR = 60∘
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