Question
Answer: Option A
:
A
From the given figure,
∠BOC = 180∘−(∠2 +∠4)
= 180∘- (∠B2 +∠C2 )
= 180∘- (180∘−∠A2)
[∵ 180∘ - ∠ A = ∠ B + ∠ C]
= 180∘- 90∘+ ∠A2
= 90∘+ ∠A2
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:
A
From the given figure,
∠BOC = 180∘−(∠2 +∠4)
= 180∘- (∠B2 +∠C2 )
= 180∘- (180∘−∠A2)
[∵ 180∘ - ∠ A = ∠ B + ∠ C]
= 180∘- 90∘+ ∠A2
= 90∘+ ∠A2
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