$$\frac{{{a^2} - {b^2} - 2bc - {c^2}}}{{{a^2} + {b^2} + 2ab - {c^2}}}$$ is equivalent to = ? Options: A . &nbsp$$\frac{{a - b + c}}{{a + b + c}}$$ B . &nbsp$$\frac{{a - b - c}}{{a - b + c}}$$ C . &nbsp$$\frac{{a - b - c}}{{a + b - c}}$$ D . &nbsp$$\frac{{a + b + c}}{{a - b + c}}$$

$$\frac{{{a^2} - {b^2} - 2bc - {c^2}}}{{{a^2} + {b^2} + 2ab

Question

$$\frac{{{a^2} - {b^2} - 2bc - {c^2}}}{{{a^2} + {b^2} + 2ab - {c^2}}}$$ is equivalent to = ?

Options:

A . $$\frac{{a - b + c}}{{a + b + c}}$$

B . $$\frac{{a - b - c}}{{a - b + c}}$$

C . $$\frac{{a - b - c}}{{a + b - c}}$$

D . $$\frac{{a + b + c}}{{a - b + c}}$$

Answer: Option C

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