Simple Equations(Quantitative Aptitude ) Questions and answers for exam Preparation

Quantitative Aptitude

SIMPLE EQUATIONS MCQs

Total Questions : 74 | Page 5 of 8 pages

Question 41.

If y is a positive integer and x = \(y - \frac{1}{y}\), then as y increases, x

decreases
increases
remains unalerted
none of these

Discuss Question

Answer: Option B. -> increases

Question 42.

The solution of \(\frac{x}{a}+ \frac{y}{b}\) = a + b and \(\frac{x}{a^{2}}+ \frac{y}{b^{2}}\) = 2 is

a , b
a² , b²
a³, b³
none of these

Discuss Question

Answer: Option B. -> a² , b²

Question 43.

Find the value of K for which the system of equations 2x + Ky = 1 and 3x - 5y = 7 has a unique solution.

\(K\neq\frac{-10}{3}\)
\(K\neq\frac{-3}{10}\)
\(K=\frac{-3}{10}\)
\(K=\frac{3}{10}\)

Discuss Question

Answer: Option A. -> \(K\neq\frac{-10}{3}\)

Question 44.

The value of K for which the system of equations 2x + 3y = 5 and 4x + Ky = 10 has an infinite number of solutions is

Discuss Question

Answer: Option B. -> 6

Question 45. Eight years ago, Ajay's age was 4/3 times that of Vijay. Eight years hence, Ajay's age will be 6/5 times that of Vijay. What is the present age of Ajay?

30 years
40 years
32 years
48 years
None of these

Discuss Question

Answer: Option B. -> 40 years

Let the present ages of Ajay and Vijay be 'A' and 'V' years respectively.
A - 8 = 4/3 (V - 8) and A + 8 = 6/5 (V + 8)
3/4(A - 8) = V - 8 and 5/6(A + 8) = V + 8
V = 3/4 (A - 8) + 8 = 5/6 (A + 8) - 8
=> 3/4 A - 6 + 8 = 5/6 A + 20/3 - 8
=> 10 - 20/3 = 10/12 A - 9/12 A
=> 10/3 = A/12 => A = 40.

Question 46. There are some rabbits and peacocks in a zoo. The total number of their heads is 60 and total number of their legs is 192. Find the number of total rabbits?

30
46
40
44
None of these

Discuss Question

Answer: Option E. -> None of these

Let the number of rabbits and peacocks be 'r' and 'p' respectively. As each animal has only one head, so r + p = 60 --- (1)
Each rabbit has 4 legs and each peacock has 2 legs. Total number of legs of rabbits and peacocks, 4r + 2p = 192 --- (2)
Multiplying equation (1) by 2 and subtracting it from equation (2), we get
=> 2r = 72 => r = 36.

Question 47. Three consecutive odd integers are in increasing order such that the sum of the last two integers is 13 more than the first integer. Find the three integers?

9, 11, 13
11, 13, 15
13, 15, 17
7, 9, 11
None of these

Discuss Question

Answer: Option D. -> 7, 9, 11

Let the three consecutive odd integers be x, x + 2 and x + 4 respectively.
x + 4 + x + 2 = x + 13 => x = 7
Hence three consecutive odd integers are 7, 9 and 11.

Question 48. On the independence day, bananas were be equally distributed among the children in a school so that each child would get two bananas. On the particular day 360 children were absent and as a result each child got two extra bananas. Find the actual number of children in the school?

600
620
500
520
None of these

Discuss Question

Answer: Option E. -> None of these

Let the number of children in the school be x. Since each child gets 2 bananas, total number of bananas = 2x.
2x/(x - 360) = 2 + 2(extra)
=> 2x - 720 = x => x = 720.

Question 49. Alok ordered 16 chapatis, 5 plates of rice, 7 plates of mixed vegetable and 6 ice-cream cups. The cost of each chapati is Rs.6, that of each plate of rice is Rs.45 and that of mixed vegetable is Rs.70. The amount that Alok paid the cashier was Rs.961. Find the cost of each ice-cream cup?

Rs.25
Rs.22.50
Rs.20
Rs.17.50
None of these

Discuss Question

Answer: Option A. -> Rs.25

Let the cost of each ice-cream cup be Rs.x
16(6) + 5(45) + 7(70) + 6(x) = 961
96 + 225 + 490 + 6x = 961
6x = 150 => x = 25.

Question 50. A man purchased 15 pens, 12 books, 10 pencils and 5 erasers. The cost of each pen is Rs.36, each book is Rs.45, each pencil is Rs.8, and the cost of each eraser is Rs.40 less than the combined costs of pen and pencil. Find the total amount spent?