Reasoning Aptitude
SERIES COMPLETION MCQs
Total Questions : 919
| Page 91 of 92 pages
Answer: Option C. -> R, R
The given sequence is a combination of two series:I: C, F, I, L, O and II: Z, X, V, T, ?The pattern in I is :C + 3 F + 3 I + 3 L + 3 O + 3 RThe pattern in II is: Z - 2 X - 2 V - 2 T - 2 R
The given sequence is a combination of two series:I: C, F, I, L, O and II: Z, X, V, T, ?The pattern in I is :C + 3 F + 3 I + 3 L + 3 O + 3 RThe pattern in II is: Z - 2 X - 2 V - 2 T - 2 R
Answer: Option C. -> L
The given sequence is a combination of two series:I: Y, T, O andII: B, G, ?I: consists of 2nd, 7th and 12th letters from the end of the English alphabet, while II: consists of 2nd, 7th and 12th letters from the beginning of the English alphabet.So, the missing letter in is the 12th letter from the beginning of the English alphabet, which is L.
The given sequence is a combination of two series:I: Y, T, O andII: B, G, ?I: consists of 2nd, 7th and 12th letters from the end of the English alphabet, while II: consists of 2nd, 7th and 12th letters from the beginning of the English alphabet.So, the missing letter in is the 12th letter from the beginning of the English alphabet, which is L.
Answer: Option C. -> VENTUR
One letter from the beginning and one from the end of a term are removed, one by one, in alternate setps,
One letter from the beginning and one from the end of a term are removed, one by one, in alternate setps,
Answer: Option C. -> UTI
In the first step, one letter from the beginning and one from the end of a term are removed to give the next term. In the second step, two letters from the beginning of a term are removed. These two steps are repeated alternately.
In the first step, one letter from the beginning and one from the end of a term are removed to give the next term. In the second step, two letters from the beginning of a term are removed. These two steps are repeated alternately.
Answer: Option C. -> L-12, N-14
The letters in the series are alternative and the numbers indicate their position in the English alphabet from the beginning.
The letters in the series are alternative and the numbers indicate their position in the English alphabet from the beginning.
Answer: Option B. -> 15LS
1st letter :1 + 4 = 5 + 4 = 9 + 4 = 13 + 4 = 17
2nd letter :C + 3 = F + 3 = I + 3 = L + 3 = O
3rd letter :V - 1 = U - 1 = T - 1 = S - 1 = R
Thus, the term 15LS is wrong and must be replaced by 13LS.
1st letter :1 + 4 = 5 + 4 = 9 + 4 = 13 + 4 = 17
2nd letter :C + 3 = F + 3 = I + 3 = L + 3 = O
3rd letter :V - 1 = U - 1 = T - 1 = S - 1 = R
Thus, the term 15LS is wrong and must be replaced by 13LS.
Answer: Option C. -> L25O
1st letter : C + 3 = F + 3 = I + 3 = L
Number : 4 (22 ) → 9 (32 ) → 16(42 ) → 25 (52 )
3rd letter : X - 3 = U - 3 = R - 3 = O
1st letter : C + 3 = F + 3 = I + 3 = L
Number : 4 (22 ) → 9 (32 ) → 16(42 ) → 25 (52 )
3rd letter : X - 3 = U - 3 = R - 3 = O
Answer: Option B. -> E
The given sequence is a combination of two series:I: M, O, R, V and II: N, L, I, ?The pattern in I is: M + 2 = O + 3 = R + 4 = VThe pattern in II is : N - 2 = L - 3 = I - 4 = ESo, the missing letter is E.
The given sequence is a combination of two series:I: M, O, R, V and II: N, L, I, ?The pattern in I is: M + 2 = O + 3 = R + 4 = VThe pattern in II is : N - 2 = L - 3 = I - 4 = ESo, the missing letter is E.
Answer: Option D. -> 22L
Numbers : 2 + 2 = 4 + 4 = 8 + 6 = 14 + 8 = 22
Letters : B + 1 = C + 2 = E + 3 = H + 4 = L
Numbers : 2 + 2 = 4 + 4 = 8 + 6 = 14 + 8 = 22
Letters : B + 1 = C + 2 = E + 3 = H + 4 = L
Answer: Option C. -> H10R
1st letter : N - 3 = K - 3 = H - 3 = E - 3 = B
Middle letter : 5 + 2 = 7 + 3 = 10 + 4 = 14 + 5 = 19
2nd letter : V - 2 = T - 2 = R - 2 = P - 2 = N
1st letter : N - 3 = K - 3 = H - 3 = E - 3 = B
Middle letter : 5 + 2 = 7 + 3 = 10 + 4 = 14 + 5 = 19
2nd letter : V - 2 = T - 2 = R - 2 = P - 2 = N
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