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MCQs

Total Questions : 81 | Page 4 of 9 pages
Question 31. The CBR is _______
  1.    \(\frac{Test \,load}{standard \,load}*100\)
  2.    \(\frac{standard \,load}{test \,load}*100\)
  3.    \(\frac{2*Test\, load}{standard \,load}*100\)
  4.    Test load*100
 Discuss Question
Answer: Option A. -> \(\frac{Test \,load}{standard \,load}*100\)
Answer: (a).\(\frac{Test \,load}{standard \,load}*100\)
Question 32. The CBR mould has internal diameter of ______
  1.    200mm
  2.    50mm
  3.    100mm
  4.    150mm
 Discuss Question
Answer: Option D. -> 150mm
Answer: (d).150mm
Question 33. The CBR values are generally calculated for penetrations of __________
  1.    2.5mm and 5mm
  2.    5mm and 7mm
  3.    7mm and 9mm
  4.    9mm and 10mm
 Discuss Question
Answer: Option A. -> 2.5mm and 5mm
Answer: (a).2.5mm and 5mm
Question 34. In general, the CBR values of 2.5mm penetration are smaller than 5mm penetration.
  1.    True
  2.    False
  3.    May be True or False
  4.    Can't say
 Discuss Question
Answer: Option A. -> True
Answer: (a).True
Question 35. For CBR test, the specimens are submerged in water for 4 days before testing.
  1.    True
  2.    False
  3.    May be True or False
  4.    Can't say
 Discuss Question
Answer: Option A. -> True
Answer: (a).True
Question 36. A base under rigid pavements is used for the ___________
  1.    preservation of pumping of fine grained soils
  2.    pumping of fine grained soils
  3.    surface coating
  4.    finishing
 Discuss Question
Answer: Option A. -> preservation of pumping of fine grained soils
Answer: (a).preservation of pumping of fine grained soils
Question 37. When load is applied on rigid pavement, it deforms in a _______
  1.    bottle shape
  2.    saucer shape
  3.    rectangular shape
  4.    square shape
 Discuss Question
Answer: Option B. -> saucer shape
Answer: (b).saucer shape
Question 38. The radius of relative stiffness is given by the characteristic equation of _______
  1.    \(l=\{\frac{eh^3}{12(1-μ^2 ) k_s}\}^\frac{1}{4}\)
  2.    \(l=\{\frac{eh^3}{12(1-μ^4 ) k_s}\}^\frac{1}{4}\)
  3.    \(l=\{\frac{eh^3}{12(1-μ^2 ) k_s}\}^\frac{1}{2}\)
  4.    \(l=\{\frac{eh^3}{12(1-μ^2 ) k_s}\}^\frac{1}{3}\)
 Discuss Question
Answer: Option A. -> \(l=\{\frac{eh^3}{12(1-μ^2 ) k_s}\}^\frac{1}{4}\)
Answer: (a).\(l=\{\frac{eh^3}{12(1-μ^2 ) k_s}\}^\frac{1}{4}\)
Question 39. A base course enables the construction to proceed during wet weather on clays and silts.
  1.    True
  2.    False
  3.    May be True or False
  4.    Can't say
 Discuss Question
Answer: Option A. -> True
Answer: (a).True
Question 40. If P is the vertical relation and ρ is the vertical deflection, then the modulus of sub-grade reaction is _______
  1.    \(k_s=\frac{P}{ρ}\)
  2.    \(k_s=\frac{1}{P}\)
  3.    \(k_s=\frac{ρ}{P}\)
  4.    \(k_s=\frac{P}{2ρ}\)
 Discuss Question
Answer: Option A. -> \(k_s=\frac{P}{ρ}\)
Answer: (a).\(k_s=\frac{P}{ρ}\)

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