x+x+1+x+2+x+3 = 4 * 56.5

=> 4x+6 = 226

=> 4x = 220

=> x = 55 = A

and C= 57

∴ A * C = 55 * 57 = 3135

4/9 = 0.44; 5/11 = 0.45;

3/7 = 0.43; 1/4 = 0.25; 2/5 = 0.4

∴ Required difference = 4/9 - 2/5 = (20-18)/45 = 2/45

Area of square = 1/2 * (diagonal)²

= (1/2) * 28 * 28 

= 392 sq.cm

Distance covered by Parag = (226 * 5 * 7)/1000 Km

= 7.91 Km

If Sarita's present age be x years, then

Kavita's present age = 2x years 

After eight years,

2x+8/x+8 = 22/13

=> 26x + 104 = 22x + 176

=> 4x = 176 - 104 = 72

=> x = 18

∴ Kavita's present age = 36 years

325 - 144 + 75 = ?² - 68

=> 256 + 68 = ?2

36 * 25 = 221 + ?

=>900 = 221 + ?

=> ? = 900 - 221 = 679

? = √49 + 289 + 25 - 2

(? *76)/100   - 121  = 525

=> ?*76/100 = 525 + 121

=> ? = 646 * 100/76

=> ? = 850

? = 4 + 1/3 + 2 + 1/6 + 6 + 1/2

= 12 + (1/3 + 1/6 + 1/2)

= 12 + ((2+1+3)/6)

= 12 + 1 

= 13