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Quantitative Aptitude

MIXTURES AND ALLEGATIONS MCQs

Alligations And Mixtures

Total Questions : 245 | Page 18 of 25 pages
Question 171. Two vessels A and B contain mixture of milk and water in the ratio 4 : 1 and 9 : 11 respectively. They are mixed in the ratio of 3 : 2. Find the ratio of milk and water in the resulting mixture.
  1.    34 : 16
  2.    17 : 33
  3.    33 : 17
  4.    16 : 34
 Discuss Question
Answer: Option C. -> 33 : 17

Quantity of milk @ Rs.10 per liter / Quantity of milk @ Rs. 16 per liter = 1 / 2 So, quantity of milk @ Rs. 10 per liter = 26 / 2 = 13 liter.2nd Method Let us assume shopkeeper buy P liter milk of price @ Rs. 10 per liter.Buy price of 26 liter of milk @ Rs. 16 per liter = 26 x 16Buy price of P liter of milk @ Rs. 10 per liter = P x 10Sell price of total milk ( P + 26 ) @ Rs. 14 per liter = 14 x ( P + 26 ) According to question there is no loss or no profit.Then Buy Price = Sell Price 26 x 16 + P x 10 = 14 x ( P + 26 ) ? 26 x 16 + 10P = 14P + 14 x 26 ? 26 x 16 - 26 x 14 = 14P - 10P? 2 x 26 = 4P? 4P = 2 x 26? P = 2 x 26 / 4 = 13So, quantity of milk @ Rs. 10 per liter = 13 liter.


Question 172. A dishonest milkman professes to sell his milk at C. P. But he mixes it with water and thereby gains 25 %. The % of water in the mixture is ?
  1.    4%
  2.    25%
  3.    None of these
  4.    20%
 Discuss Question
Answer: Option D. -> 20%
Question 173. A shopkeeper buys 26 liter of milk @ Rs. 16 per liter. He also buys from another source an inferior quality of milk @ Rs. 10 per liter. How much quantity of the later should he buy to mix it with the former so that he can sell the mixture @ Rs. 14 per liter without making any loss?
  1.    12 liter
  2.    16 liter
  3.    14 liter
  4.    13 liter
 Discuss Question
Answer: Option D. -> 13 liter

Quantity of milk @ Rs.10 per liter / Quantity of milk @ Rs. 16 per liter = 1 / 2 So, quantity of milk @ Rs. 10 per liter = 26 / 2 = 13 liter.2nd Method Let us assume shopkeeper buy P liter milk of price @ Rs. 10 per liter.Buy price of 26 liter of milk @ Rs. 16 per liter = 26 x 16Buy price of P liter of milk @ Rs. 10 per liter = P x 10Sell price of total milk ( P + 26 ) @ Rs. 14 per liter = 14 x ( P + 26 ) According to question there is no loss or no profit.Then Buy Price = Sell Price 26 x 16 + P x 10 = 14 x ( P + 26 ) ? 26 x 16 + 10P = 14P + 14 x 26 ? 26 x 16 - 26 x 14 = 14P - 10P? 2 x 26 = 4P? 4P = 2 x 26? P = 2 x 26 / 4 = 13So, quantity of milk @ Rs. 10 per liter = 13 liter.


Question 174. A shopkeeper has 50 kgs of rice. He sells a part of it at 20% profit and the rest at 40% profit. If he gains 25% on the whole, find the quantity of each part.
  1.    37.5 kgs and 12.5 kgs
  2.    12.5 kgs and 37.5 kgs
  3.    23.5 kgs and 21.5 kgs
  4.    21.5 kgs and 23.5 kgs
 Discuss Question
Answer: Option A. -> 37.5 kgs and 12.5 kgs

According to figure we find that the ratio will be 3 : 1.Quantity sold at 20% profit = 3 / (3 + 1) × 50 = 37.5 kgs. Quantity sold at 40% profit = (50 ? 37.5) = 12.5 kgs.


Question 175. The average monthly salary of employees, consisting of officers and workers, of an organisation is Rs. 3000. The average salary of an officer is Rs. 10,000 while that of a worker is Rs. 2000 per month. If there are total 400 employees in the organisation, find the number of officers and workers separately.
  1.    250 , 150
  2.    310 , 90
  3.    50 , 350
  4.    300 , 100
 Discuss Question
Answer: Option C. -> 50 , 350

As per figure we can calculate the ration as belowNumber of officers / Number of workers = 1000 / 7000 = 1 / 7 No. of officers = 1 / (1 + 7) × 400 = 50 No. of workers = 400 ? 50 = 350


Question 176. 6 liters of milk and water mixture has 75% milk in it. How much milk should be added to the mixture to make it 90% pure?
  1.    9 liters
  2.    12 liters
  3.    10 liters
  4.    8 liters
 Discuss Question
Answer: Option A. -> 9 liters

The given solution has 75% milk.
Milk to be added has 100% milk.
Milk should be added to the given mixture in the ratio 15 : 10 or 3 : 2
Quantity of milk to be added = (3 / 2) × 6 = 9 liters.


Question 177. If 4 kg of an alloy made of 1/4th iron and rest is mixed with 6 kg of another alloy made of 2/3rd iron and rest tin, find the ratio of iron to tin in the resultant mixture.
  1.    1 : 2
  2.    1 : 1
  3.    3 : 2
  4.    2 : 1
 Discuss Question
Answer: Option B. -> 1 : 1

Total quantity of iron = 4 (1 / 4) + 6 (2 / 3) = 1 + 4 = 5 kg. Total quantity of tin = (4 + 6) ? 5 = 5 kg. In the resultant mixture, iron : tin = 5 : 5 or 1 : 1


Question 178. In what ratio must water be added to spirit to gain 25% by selling it at cost price?
  1.    1 : 4
  2.    4 : 3
  3.    4 : 1
  4.    3 : 4
 Discuss Question
Answer: Option A. -> 1 : 4

Let cost price of spirit be Re. 1 per liter. Then SP of mixture = Re. 1 per liter Gain = 25% So, CP of mixture = 1 × (100 / 125) = Re. 4 / 5We assume that CP of water is zero. Using allegation rule on cost price, Water should be mixed to spirit in the ratio (1 / 5) : (4 / 5) or 1 : 4


Question 179. 729 ml. of a mixture contains milk and water in the ratio 7 : 2. How much more water is to be added to get a new mixture containing milk and water in ratio 7 : 3?
  1.    None of these
  2.    710 ml
  3.    600 ml
  4.    520 ml
 Discuss Question
Answer: Option A. -> None of these

Let C.P. of 1 liter milk be Re. 1, Gain = 16 2/3 % = 50/3 %and S.P. of 1 liter mixture = Re. 1 then C.P. of 1 liter mixture = (1 x (100 x 3) / 350) = Re. (6 / 7) By the rule of alligation,Hence, required ratio = (1/ 7) : (6 / 7) = 1 : 6


Question 180. In what ratio of water be mixed with milk to gain 16 2/ 3 % on selling the mixture at cost price?
  1.    1 : 6
  2.    6 : 1
  3.    4 : 3
  4.    2 : 3
 Discuss Question
Answer: Option A. -> 1 : 6

Let C.P. of 1 liter milk be Re. 1, Gain = 16 2/3 % = 50/3 %and S.P. of 1 liter mixture = Re. 1 then C.P. of 1 liter mixture = (1 x (100 x 3) / 350) = Re. (6 / 7) By the rule of alligation,Hence, required ratio = (1/ 7) : (6 / 7) = 1 : 6


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