Quantitative Aptitude
MENSURATION MCQs
Regular Polygons, Triangles, Circles
Total Questions : 254
| Page 6 of 26 pages
Answer: Option A. -> 10 cm
:
A
Given that
The diameter of a circle = 20 cm
The radius of a circle = Diameter2
On substituting the values we get:
The radius of the circle =202=10cm
:
A
Given that
The diameter of a circle = 20 cm
The radius of a circle = Diameter2
On substituting the values we get:
The radius of the circle =202=10cm
Answer: Option B. -> 30cm
:
B
Radius =15 cm
Diameter =2×radius
= 2×15
= 30 cm
:
B
Radius =15 cm
Diameter =2×radius
= 2×15
= 30 cm
Answer: Option B. -> 16 cm
:
B
Given that
The diameter of a circle = 32 cm
The radius of a circle = Diameter2
On substituting the values we get:
The radius of the circle whose diameter is 32 cm=322=16cm
:
B
Given that
The diameter of a circle = 32 cm
The radius of a circle = Diameter2
On substituting the values we get:
The radius of the circle whose diameter is 32 cm=322=16cm
Answer: Option C. -> 14cm
:
C
In a circle of radius 6cm, the diameter will be 12 cm.
A chord is a line segment with its endpoints on the circle and we know that diameter of a circle is the largest chord of the circle.
So a chord cannot be longer than 12cm.
:
C
In a circle of radius 6cm, the diameter will be 12 cm.
A chord is a line segment with its endpoints on the circle and we know that diameter of a circle is the largest chord of the circle.
So a chord cannot be longer than 12cm.
Answer: Option C. -> 48 cm
:
C
Given that
The length of the diameter of a circle = 96 cm
We know that,radius of a circle = Diameter2
On substituting the values we get:
Radius of circle = 962=48cm
:
C
Given that
The length of the diameter of a circle = 96 cm
We know that,radius of a circle = Diameter2
On substituting the values we get:
Radius of circle = 962=48cm
Answer: Option B. -> 96 cm
:
B
Given that
The radius of a circle = 48 cm
The diameter of a circle = radius × 2
On substituting the values we get;
The diameter of the circle = 48 × 2 = 96 cm
:
B
Given that
The radius of a circle = 48 cm
The diameter of a circle = radius × 2
On substituting the values we get;
The diameter of the circle = 48 × 2 = 96 cm
Answer: Option D. -> BC, AD
:
D
The chords of the given circle are AB, CD, BC and AD.
The diameter of a circle is its longest chord.
Since BC and AD pass through the center(O) of the circle, they are the diameters of the circle and hence, the longest chords.
:
D
The chords of the given circle are AB, CD, BC and AD.
The diameter of a circle is its longest chord.
Since BC and AD pass through the center(O) of the circle, they are the diameters of the circle and hence, the longest chords.
Answer: Option C. -> both 3 and 6
:
C
Given that
The radius of a circle is a multiple of 3.
So, the radius of the circle can be 3n, where n is any natural number.
Now, Diameter of a circle = radius × 2 = 3n× 2 = 6 ×n
Hence, the diameter of the circle is a multiple of both 3 and 6.
:
C
Given that
The radius of a circle is a multiple of 3.
So, the radius of the circle can be 3n, where n is any natural number.
Now, Diameter of a circle = radius × 2 = 3n× 2 = 6 ×n
Hence, the diameter of the circle is a multiple of both 3 and 6.
Answer: Option A. -> 12 cm
:
A
Given that
The radius of a circle is 4 cm.
The diameter of the circle = 4 × 2 = 8 cm
The diameter is the longest chord of a circle. Hence, the length of any chord cannot be more than 8 cm.
:
A
Given that
The radius of a circle is 4 cm.
The diameter of the circle = 4 × 2 = 8 cm
The diameter is the longest chord of a circle. Hence, the length of any chord cannot be more than 8 cm.
Latest Videos
Latest Test Papers
Login With Google
Old way of Login
Login With Email