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MCQs

Total Questions : 141 | Page 3 of 15 pages
Question 21. In the following figure, what is the value of I?In The Following Figure, What Is The Value Of I?
  1.    I = Iᵥ + Iᵣ
  2.    I = Iᵥ – Iᵣ
  3.    I = Iᵥ Iᵣ
  4.    I = Iᵥ ⁄ Iᵣ
 Discuss Question
Answer: Option A. -> I = Iᵥ + Iᵣ
Answer: (a).I = Iᵥ + Iᵣ
Question 22. A resistance R is measured using the connection shown in the below figure.
The current measured is 10 A on ranges 100A and the voltage measured is 125 V on 150 V range. The scales of the ammeter and voltmeter are uniform. The total number of scale divisions of the ammeter is 100 and that of the voltmeter is 150. The scale division can be distinguished. The constructional error of the ammeter is ± 0.3% and that of voltmeter±0.4%. The resistance of the ammeter is 0.25 Ω.
The possible error in the measurement of R is?A Resistance R Is Measured Using The Connection Shown In The...
  1.    ±0.11 Ω
  2.    ±0.15 Ω
  3.    ±0.867 Ω
  4.    ±0.625 Ω
 Discuss Question
Answer: Option A. -> ±0.11 Ω
Answer: (a).±0.11 Ω
Question 23. Circuit shows the method of Measurement of low resistance by Ammeter-Voltmeter method. What is the percentage error?Circuit Shows The Method Of Measurement Of Low Resistance By...
  1.    Zero
  2.    \(\frac{R_x}{R_x + R_v} × 100\)
  3.    \(– \frac{R_x}{R_x + R_v} × 100\)
  4.    \(– \frac{R_v}{R_x + R_v} × 100\)
 Discuss Question
Answer: Option C. -> \(– \frac{R_x}{R_x + R_v} × 100\)
Answer: (c).\(– \frac{R_x}{R_x + R_v} × 100\)
Question 24. A resistance R is measured using the connection shown in the below figure.
The current measured is 10 A on ranges 100A and the voltage measured is 125 V on 150 V range. The scales of the ammeter and voltmeter are uniform. The total number of scale divisions of the ammeter is 100 and that of the voltmeter is 150. The scale division can be distinguished. The constructional error of the ammeter is ± 0.3% and that of voltmeter±0.4%. The resistance of the ammeter is 0.25 Ω.
The value of R is?A Resistance R Is Measured Using The Connection Shown In The...
  1.    12.75 Ω
  2.    12.0 Ω
  3.    12.25 Ω
  4.    12.5 Ω
 Discuss Question
Answer: Option C. -> 12.25 Ω
Answer: (c).12.25 Ω
Question 25. Circuit shows the method of Measurement of low resistance by Ammeter-Voltmeter method. The measured resistance Rm for the given Circuit is _________Circuit Shows The Method Of Measurement Of Low Resistance By...
  1.    Rₓ + Rᵥ
  2.    \(\frac{R_x^2}{R_x + R_v}\)
  3.    \(\frac{R_v^2}{R_x + R_v}\)
  4.    \(\frac{R_x R_v}{R_x + R_v}\)
 Discuss Question
Answer: Option D. -> \(\frac{R_x R_v}{R_x + R_v}\)
Answer: (d).\(\frac{R_x R_v}{R_x + R_v}\)
Question 26. What is the main source of error in a null detector?
  1.    lower current detection ability
  2.    insufficient sensitivity of the null detector
  3.    wiring resistance
  4.    power dissipation
 Discuss Question
Answer: Option B. -> insufficient sensitivity of the null detector
Answer: (b).insufficient sensitivity of the null detector
Question 27. What is the effect of the increase in temperature on the resistance elements?
  1.    directly proportional
  2.    independent
  3.    inversely proportional
  4.    changes by a factor of 10
 Discuss Question
Answer: Option A. -> directly proportional
Answer: (a).directly proportional
Question 28. The main error when measuring low resistances is _________
  1.    power dissipation of the arms
  2.    voltage drop across the emf source
  3.    lead and contact resistance
  4.    current flowing through the circuit
 Discuss Question
Answer: Option C. -> lead and contact resistance
Answer: (c).lead and contact resistance
Question 29. When current passes through the resistances in the Wheatstone bridge what happens?
  1.    voltage drop occurs
  2.    null detector burns
  3.    back emf is induced
  4.    temperature increases due to power dissipation
 Discuss Question
Answer: Option D. -> temperature increases due to power dissipation
Answer: (d).temperature increases due to power dissipation
Question 30. Heating effect in the Wheatstone bridge can be avoided by _________
  1.    using an expensive emf source
  2.    limiting current to a safe value
  3.    using heating sinks
  4.    immersing the setup in ice
 Discuss Question
Answer: Option B. -> limiting current to a safe value
Answer: (b).limiting current to a safe value

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