Reasoning Aptitude
MATHEMATICAL OPERATIONS MCQs
J ≤ D -- (i); Q ≥ D -- (ii); Q < M -- (iii)combining (i) and (ii), we get:Q ≥ D ≥ J => Q > J (conclusion I) or Q = J (conclusion II).Hence, either conclusion I or conclusion II is true.
B = K -- (i); K < D -- (ii); D ≥ M -- (iii)From (i) and (ii), we get: D ≥ K = B -- (iv)from (iii) and (iv), no specific relation can be obtained between B and M. Therefore, B = M (conclusion I) and B < M (conclusion II) are not necessarily true.
F ≥ G -- (i); N = G -- (ii); N > T -- (iii)combining all, we getF ≥ G = N > T => N ≤ F (conclusion II) and T > F.Hence, conclusion I (T > F) is not true but conclusion II is true.
H < N -- (i); N > W -- (ii); W ≥ V -- (iii)From (ii) and (iii), we get N > W ≥ V --- (iv)From (i) and (iv), no specific relation can be obtained between H and V. Hence, H < V (conclusion I) is not necessarily true. But V < N (conclusion II) follows from equation (iv).
D > B -- (i); B ≤ T -- (ii); T < M -- (iii)Combining (ii) and (iii), we getM > T ≥ B => M > B (conclusion I) and T ≥ B (conclusion II).
M < K -- (i); K = D -- (ii); D ≤ P -- (iii)Combining all the equations, we get:P ≥ D = K > M => p > M. Hence, conclusion I (M ≤ P) and conclusion II (M = P) are not true.
H = D -- (i); D > R -- (ii); R ≥ N -- (iii)Combining (i) and (ii), we get:R > H = D -- (iv)From (iii) and (iv), we can't get any specific relation between N and H. Therefore, conclusion I (N = H) and conclusion II (N > H) are not true.
W ≥ T -- (i); T > M -- (ii); B < M -- (iii)Combining all, we get W ≥ T > M > B=> W > B and W > M. Hence, both conclusions (W > B; M < W) are true.
Z ≤ R -- (i); R ≥ D -- (ii); D < T -- (iii)With these equations no relation can be established between D and Z, and Z and T.
M > R --- (i) R ≥ K --- (ii) J < K --- (iii)combining (i), (ii) and (iii), we get:M > R ≥ K > J => M > J (conclusion I),R > J (conclusion II),M > K (conclusion III),Hence, conclusion I (M > J), conclusion II (J < R) and conclusion III (K < M) are all true.