9th Grade > Mathematics
LINES AND ANGLES MCQs
Lines And Angles
:
A
The sum of two complementary angles is 90∘. Hence, each angle will be less than 90∘
:
A
In the above figure, since the two lines are parallel and cut by a transversal, using the property of corresponding angles:
⇒ 2x - 60∘ = x
⇒ x - 60∘ = 0
⇒ x = 60∘
:
A
From the given figure,
∠BOC = 180∘−(∠2 + ∠4)
      = 180∘ - (∠B2 + ∠C2 )         Â
      = 180∘ - (180∘−∠A2) Â
          [∵ 180∘ - ∠A = ∠B + ∠C]
      = 180∘ - 90∘ + ∠A2
      = 90∘ + ∠A2
:
A
Let ∠1 = 3x and ∠2 = 2x
Sum of angles on a straight line is 180∘.
So, 3x + 2x = 180∘
⇒ 5x = 180∘
⇒ x = 36∘
⇒∠6 = ∠2    [∵∠6 and ∠2 are corresponding angles]
⇒ ∠6 = 2x = 2 × 36 = 72∘Â
Hence, ∠6 = 72∘
:
From â–³ ABC;
∠A+∠B+∠C=180∘
From â–³ DEF;
∠D+∠E+∠F=180∘
So, adding these
∠A+∠B+∠C+∠D+∠E+∠F=180∘+180∘=360∘
:
B
From the given figure,
∠ECD=180∘−150∘=30∘ (sum of interior angles on the same side of the transversal is 180°)
x=∠BCD=25∘+∠ECD (alternate interior angles)
=25∘+30∘=55∘
:
B
yx=5
⇒y=5x and
zx=4
⇒z=4x
x∘+y∘+z∘=180∘
x∘+5x∘+4x∘=180∘
10x∘=180∘
x=18∘
:
C and D
If two angles form a linear pair, either both of them are 90∘ or one angle is acute and the other is obtuse. They cannot both be acute angles because in that case the sum would not be 180∘ .
:
C
x + 2x + 3x = 180∘ [Angles on a straight line]
6x = 180∘
x = 30∘