9th Grade > Mathematics
LINEAR EQUATIONS IN TWO VARIABLES MCQs
:
A
A linear relation between two variables is geometrically represented by a straight line on the Cartesian plane.
:
D
A linear equation in two variables is of the form x+by+c=0
⇒x=−c−by
For every unique value of x, we get a unique value of y satisfying the above equation. Therefore, a linear equation in two variables can have infinitely many solutions.
:
D
By looking at the graph we can easily say that the line passes through the points (2,0) and (0,-4).
We can identify which line passes through these points by substituting the points in the equation of the line.
Plugging x = 2, y = 0 in equation y = 2x - 4, we get
0 = 2(2) - 4 = 0
Plugging x = 0, y = -4 in equation y = 2x - 4, we get
-4 = 2(0) - 0 = -4
The equation y = 2x - 4 is satisfied by both the points. So, given graph belongs to y = 2x - 4.
:
A and B
The given equation is 4x + y = 16.
(i) (0, 16)
Putting x = 0 and y = 16 in the given equation:
LHS = (4 × 0) + 16 = 16 (RHS)
Thus, (0, 16) is a solution of the given equation.
(ii) (4, 0)
Putting x = 4 and y = 0 in the given equation:
LHS = (4 × 4) + 0 = 16 (RHS)
Thus, (4, 0) is a solution of the given equation.
(iii) (0, 8)
If we put x = 0 and y = 8 in the given equation:
4(0)+8=8≠16(RHS), and thus (0, 8) is not a soltuion of the given equation.
(iv) (3, 2)
Similarly, putting x = 3 and y = 2 in the given equation, we get 4(3)+2=14≠16(RHS), and thus (3, 2) is also not a soltuion of the given equation.
:
D
If a=−1,b=4 is the solution of equation −2a=−5b+k, then they will satisfy the given equation.
Putting values of a & b in the given equation.
So,
−2(−1)=−5(4)+k2=−20+k⇒k=20+2⇒k=22.
Therefore, the value of k is 22.
:
A
Given, the price of 1 kg of oranges is x and that of 1 kg of apples is y.
According to the given condition, the price of the 1 kg oranges is three times the price of the 1 kg apple.
So, x = 3y.
Therefore, x - 3y = 0
:
A
x + y = 0
⇒ x = - y or y = - x
If x = a, y = -a
∴ Any point on the line x + y = 0 can be represented as (a,-a)