6th Grade > Mathematics
KNOWING OUR NUMBERS MCQs
Total Questions : 99
| Page 4 of 10 pages
Answer: Option C. -> 3×10000+4×1000+8×100+7×10+9×1
:
C
In 34879, 3 is in 10000's place, 4 is in 1000's place, 8 is in 100's place, 7 is in 10's place and 9 is in 1's place.
So,34879=3×10000+4×1000+8×100+7×10+9×1
:
C
In 34879, 3 is in 10000's place, 4 is in 1000's place, 8 is in 100's place, 7 is in 10's place and 9 is in 1's place.
So,34879=3×10000+4×1000+8×100+7×10+9×1
Answer: Option A. -> Whole numbers
:
A
Whole numbers startfrom 0 and it is the number system which starts withthe predecessor of 1.
:
A
Whole numbers startfrom 0 and it is the number system which starts withthe predecessor of 1.
Answer: Option B. -> False
:
B
In a set of natural numbers, the largest number cannot be determined.
:
B
In a set of natural numbers, the largest number cannot be determined.
:
Forty lakh seventy thousand and eight = 40,70,008.
:
Place value of 6 at I = 6000
Place value of 6 at II = 60
⇒Place value of 6 at IPlace value of 6 at II=600060
= 100
Answer: Option B. -> Natural Numbers
:
B
Natural numbers start from number 1.
:
B
Natural numbers start from number 1.
Answer: Option B. -> Selling Price = ₹ 37.5, Round off value of the articles = ₹ 410
:
B
Selling Price \(= ₹( 50 - 12.5) = ₹ 37.5\)
Selling priceof 11 articles \(= 11\times 37.5 = ₹412.5\)
412.50 rounded off to the nearest tens is 410.
:
B
Selling Price \(= ₹( 50 - 12.5) = ₹ 37.5\)
Selling priceof 11 articles \(= 11\times 37.5 = ₹412.5\)
412.50 rounded off to the nearest tens is 410.
Question 38. Ram and Shyam were playing. Ram asks Shyam to form numbers with the digits 4,3, 8 and 1. He gives him three different cases as
i. Form the largest four digit number with no repetition of digits.
ii. Form the largest four digit where two digits can be repeated twice.
iii. Form the smallest four digit number where repetition of digits is allowed four times.
What are the numbers?
i. Form the largest four digit number with no repetition of digits.
ii. Form the largest four digit where two digits can be repeated twice.
iii. Form the smallest four digit number where repetition of digits is allowed four times.
What are the numbers?
Answer: Option B. -> i-8431, ii-8844, iii-1111
:
B
Four digit greatest numberwith no repetition of digits, is 8431
Four digit greatest number where a digit can be repeated twice 8844
Smallest four digits where repetition of digits is allowed - 1111
:
B
Four digit greatest numberwith no repetition of digits, is 8431
Four digit greatest number where a digit can be repeated twice 8844
Smallest four digits where repetition of digits is allowed - 1111
Question 39. Akash asked Pavan to find the value of 9999×(555). He says that it will be difficult to multiply as both of them are big numbers. Akash says that there is a simple way to find the product. He solves the problem using the concept of brackets. Which of the following will be the easiest way to solve this?
Answer: Option D. -> 9999×(555)=(10000−1)×(555)
:
D
As 9999 is nothing but (10000 - 1) and it's very easy to multiply any number with a multiple of 10.
∴ Easiest way to solve 9999×555 will be(10000−1)×(555).
:
D
As 9999 is nothing but (10000 - 1) and it's very easy to multiply any number with a multiple of 10.
∴ Easiest way to solve 9999×555 will be(10000−1)×(555).
Answer: Option C. -> Greatest- 98320, Smallest-20389
:
C
Greatest number that can be formed using 0, 8, 3, 9 and 2 is98320.
Smallest number that can be formed using 0, 8, 3, 9 and 2 is 20389.
02389 would not be the smallest number as it will be a 4 digit number formed by the given digits.
:
C
Greatest number that can be formed using 0, 8, 3, 9 and 2 is98320.
Smallest number that can be formed using 0, 8, 3, 9 and 2 is 20389.
02389 would not be the smallest number as it will be a 4 digit number formed by the given digits.
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