Answer: Option B. -> False
:
B
The reciprocal of $\frac{1}{6}$is 6

Answer: Option D. -> Only iv
:
D
(i) All the negative integers are less than 0.
(ii) Multiplicative identity for integers is same as that of whole numbers i.e., 1.
(iii) Absolute value of a non-negativeintegeris equal to the integer itself and the absolute value of a negative integer is always greater than the integer.
E.g. absolute value of 6 is 6; absolute value of -6 is 6.
(iv) Every negative integer is less than anynatural number.

Answer: Option D. -> 33∘C
:
D
Here,
$\text{Lowest temperature}=-{10}^{\circ }C\text{Temperature rise}={43}^{\circ }C\text{Maximum temperature}=(-10+43)={33}^{\circ }C$
$\therefore$The maximum temperature is ${33}^{\circ }C$.

:
Distance and direction: 2 Marks
Total Distance: 1 Mark
Distance travelled by Ram in the north direction = 20km
Distance travelled in the south direction = 45km
Ram's distance from theinitial point = (45 - 20 ) = 25km
Ram is 25km in the south direction from his starting point.
The total distance travelled by Ram = 20 + 45 = 65km

:
Each question: 1 Mark
Rate at which climber climbs the hill = 3 m/s
Total distance to be climbed by the climber = 200m - 20m = 180m
The time required by the climber to reach the top of the hill is
$=\frac{180}{3}$
= 60 seconds
Hence, the climber will climb the hill in 60 seconds.
It is given that he covered half of the distance at 3 m/s and the remaining half at 2 m/s.
Total distance to be covered = 180m
Distance covered with speed3 m/s = $\frac{180}{2}$
= 90m
Distance covered with speed 2 m/s
= 180-90 = 90m
Time taken to cover the first 90m = $\frac{90}{3}$
= 30 seconds
Time taken to cover the last 90m =$\frac{90}{2}$
= 45 seconds
The total time taken to climb to the top of the hill = 30 + 45 = 75 seconds

:
Each question - 1 Mark
Team A - 40, 10, 0.
Total score = - 40 + 10 + 0 = - 30
Team B - 20, 0,- 40.
Total score = 20 + 0 +(- 40) = - 20
Team C - 30, 30, 20
Total score = 30 + 30 + 20 = 80
Team D - 80, -20, 10
Total score = 80 - 20 + 10 = 90
(i) So, team D scored the highest = 90
(ii) Team A scored the lowest =-30
(iii) The difference between the highest scorer and the lowest scorer
= 90 - (-30) = 90 + 30 = 120
(iv)Yes, we can add integers in any order. We had observed that the scores obtained by both teams in successive rounds were numerically equal but different in order. Yet, the total score of both teams was equal. It is the associative property of addition of integers.

:
Definition: 1 Mark
Example: 1 Mark
When we add zero to any whole number, we will get the same whole number as result. Hence, zero is known as additive identity.
For example, 5 + 0 = 0, here 0 is the additive identity
The additive inverse of a number is the number that when added, yields zero. To find the additive inverse of a number, we multiply the given number by -1.
For example, if we want to find the additive inverse of the number 5 we multiply it by -1.
$5\times (-1)=(-5)$
So, -5 is the additive inverse of the number 5.

:
Writing the factors: 1 Mark
Answer: 1 Mark
Here, -12 can be written as $(-1\times 12)$, $(-2\times 6)$, $(-3\times 4)$, $(-4\times 3)$, $(-6\times 2)$ and $(-12\times 1)$.
So, -12 can be written in 6 ways as a product of two integers.

:
First attempt: 2 Marks
Second Attempt: 2 Marks
Distance of the bird from the ground surface in the first attempt = 1200m
Distance of the hunter from the ground surface = 600m
Distance of the bird from the hunter
= 1200m - 600m = 600m
But, when the hunter stands, the height of the gun from ground = 600 + 1 = 601m
So, distance traveled by bullet in the first attempt= 1200 - 601= 599m
Distance of the bird from the ground surface in the secondattempt = 1300m
Distance traveled by the bullet inthe second attempt= 1300 - 601 = 699m

:
Each option: 2 Marks
a)625$\times$ (−35) + (−625)$\times$ 65
= 625$\times$ [(−35) + (−65)]
($\because$ (a$\times$ b) + (a$\times$ c) = a$\times$ (b + c))
= 625$\times$ (−100) = −62500
b)(−17)$\times$ (−29)
= (−17)$\times$ [−30 + 1]
= [(−17)$\times$ (−30)] + [(−17) $\times$ 1]
($\because$ a$\times$ (b + c) = (a$\times$ b) + (a$\times$ c)
= (510) + (−17) = 493