MCQs
Total Questions : 75
| Page 4 of 8 pages
Answer: Option B. -> t = t0 at x = 0 and t = ta at x = infinity
Answer: (b).t = t0 at x = 0 and t = ta at x = infinity
Answer: (b).t = t0 at x = 0 and t = ta at x = infinity
Question 32. Let us say there are two rods having same dimensions, one made of brass (k = 85W/m K) and the other of copper (k = 375W/m K), having one of their ends inserted into a furnace. At a section 10.5 cm away from the furnace, the temperature of brass rod is 120 degree Celsius. Find the distance at which the same temperature would be reached in the copper rod? Both ends are exposed to the same environment
Answer: Option D. -> 22.05 cm
Answer: (d).22.05 cm
Answer: (d).22.05 cm
Answer: Option C. -> t – t a/t₀ – t a = e-m x
Answer: (c).t – t a/t₀ – t a = e-m x
Answer: (c).t – t a/t₀ – t a = e-m x
Answer: Option A. -> (h P k A)^1/2 (t₀ – t a)
Answer: (a).(h P k A)^1/2 (t₀ – t a)
Answer: (a).(h P k A)^1/2 (t₀ – t a)
Question 35. Three rods, one made of silver (l = 420W/m K), second made of aluminum (k = 210W/m K) and the third made of iron (k = 70W/m K) are coated with a uniform layer of wax all around. The rods are placed vertically in a boiling water bath with 250 mm length of each rod projecting outside. If all the rods are having following dimensions i.e. diameter = 15 mm and length = 300 mm and have identical surface coefficient 12.5W/ m² K, work out the ratio of lengths up to which wax will melt on each rod
Answer: Option C. -> 2.45:1.732:1
Answer: (c).2.45:1.732:1
Answer: (c).2.45:1.732:1
Answer: Option A. -> 6.84W
Answer: (a).6.84W
Answer: (a).6.84W
Answer: Option C. -> Convective heat transfer from the fin surface
Answer: (c).Convective heat transfer from the fin surface
Answer: (c).Convective heat transfer from the fin surface
Answer: Option D. -> The temperature drop along the length will be steeper
Answer: (d).The temperature drop along the length will be steeper
Answer: (d).The temperature drop along the length will be steeper
Answer: Option B. -> L C = L + a/4(3)^1/2
Answer: (b).L C = L + a/4(3)^1/2
Answer: (b).L C = L + a/4(3)^1/2
Answer: Option B. -> t = t₀ at x = 0 and d t/d x = 0 at x = 1
Answer: (b).t = t₀ at x = 0 and d t/d x = 0 at x = 1
Answer: (b).t = t₀ at x = 0 and d t/d x = 0 at x = 1