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12th Grade > Chemistry

HALOALKANES AND HALOARENES MCQs

Total Questions : 30 | Page 1 of 3 pages
Question 1. Biphenyl is obtained by treating chlorobenzene with Na metal in presence of ether, the reaction is called as :
  1.    Wurtz reaction
  2.    Fittig reaction
  3.    Wurtz-Fittig reaction
  4.    None
 Discuss Question
Answer: Option B. -> Fittig reaction
:
B
When 2 molecules of same aryl halides reacts in presence of Na metal the reaction is called as Fittig reaction
Question 2. The reaction  The Reaction   Is Known As is known as
  1.    Wurtz reaction
  2.    Fitting reaction
  3.    Wurtz-Fitting reaction
  4.    Freund reaction
 Discuss Question
Answer: Option D. -> Freund reaction
:
D
Conversion of α,ω-dihalogen derivatives to cycloalkanes using Na and ether is Freund’s reaction.
Question 3. Which of the following are arranged in the decreasing order of dipole moment?
  1.    CH3Cl,CH3Br,CH3F
  2.    CH3Cl,CH3F,CH3Br
  3.    CH3Br,CH3Cl,CH3F
  4.    CH3Br,CH3F,CH3Cl
 Discuss Question
Answer: Option B. -> CH3Cl,CH3F,CH3Br
:
B
Due to much smaller size of F than Cl, the dipole moment of CH3F is lower than that of CH3Cl.
Question 4. Chloropicrin is
  1.    Picric acid
  2.    Nitrochloroform
  3.    Nitromethane
  4.    Nitroethyl chloride
 Discuss Question
Answer: Option B. -> Nitrochloroform
:
B
Chloroform on nitration with nitrating mixture gives chloropicrin
Chloropicrin Is
Question 5. Arrange the following compounds in increasing order of their boiling points.
I. CH3CH2CH2Br
II. CH3CH2CH2CH2Br
III.(CH3)2CHCH2Br
IV. (CH3)3CBr
  1.    II
  2.    III
  3.    IV
  4.    I
 Discuss Question
Answer: Option D. -> I
:
D
Boiling points increases as the number of carbon atoms increases in the alkyl halides. Therefore the B.P of II, III and IV with four carbon atoms is higher than that of I with three carbon atoms. Further, the B.P decreases with the number of branches. Thus the B.P of the four alkyl halides increases in the order I< IV< III< II.
Question 6. The Reagent For The Above Conversion Is
The reagent for the above conversion is
  1.    Alcoholic KOH
  2.    Alcoholic KOH followed by  NaNH2
  3.    Aqueous KOH followed by NaNH2
  4.    Zn/ CH3COOH
 Discuss Question
Answer: Option B. -> Alcoholic KOH followed by  NaNH2
:
B
The Reagent For The Above Conversion Is
Question 7. Arrange the following: CH3CH2CH2CH2Cl (I), CH3CH2CHClCH3 (II), (CH3)2CHCH2Cl (III) and (CH3)3CCl (IV) in order of decreasing tendency towards SN2 reaction
  1.    I>III>II>IV
  2.    III>IV>II>I
  3.    II>I>III>IV
  4.    IV>III>II>I
 Discuss Question
Answer: Option A. -> I>III>II>IV
:
A
Reactivity decreases as the steric hinderance increases for SN2 reaction
Question 8. C6H5CH3|C|HBr+H2OHOCH3|C|HC6H5 + HBr
The above reaction results in 98% racemization. The reaction mainly follows
  1.    SN1 mechanism
  2.    SN2 mechanism
  3.    E1 mechanism
  4.    E2 mechanism
 Discuss Question
Answer: Option A. -> SN1 mechanism
:
A
The outgoing nucleophile does not leave the reactant and therefore, attack is mainly from backside .
Question 9. Which is used in the manufacture of plastic 
 Discuss Question
Answer: Option A. -> SN1 mechanism
:
A
Which Is Used In The Manufacture Of Plastic 
Question 10. In the solvolysis of 3-methyl-3-bromohexane, which of the following statements is not correct?
  1.    The intermediate involves sp2−carbon
  2.    Polar solvents accelerate the reaction    
  3.    The rate of the reaction depends upon 3-methyl-3-bromohexane concentration
  4.    It involves inversion of configuration
 Discuss Question
Answer: Option D. -> It involves inversion of configuration
:
D
3-methyl-3-bromohexane is a 30 alkyl halide and undergoes solvolysis by SN1 mechanism followed byracemization.

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