9th Grade > Physics
GRAVITATION MCQs
Total Questions : 58
| Page 2 of 6 pages
Answer: Option A. -> same in all directions
:
A
In a liquid, pressure acts in all directions equally. Due to this, pressure acts on both the horizontal walls of the container and its base.
:
A
In a liquid, pressure acts in all directions equally. Due to this, pressure acts on both the horizontal walls of the container and its base.
Answer: Option A. -> 9.49×10−10 N
:
A
Given:
mass of first body m1=40kg
mass of second body m2=80kg
distance between two bodies, R=15m
G=6.673×10−11Nm2kg−2
Acc. to Newton's law of gravitation, Gravitational force, F=Gm1m2R2
So, F=6.673×10−11×40×80152
On solving, we get F=9.49×10−10N
:
A
Given:
mass of first body m1=40kg
mass of second body m2=80kg
distance between two bodies, R=15m
G=6.673×10−11Nm2kg−2
Acc. to Newton's law of gravitation, Gravitational force, F=Gm1m2R2
So, F=6.673×10−11×40×80152
On solving, we get F=9.49×10−10N
Answer: Option D. -> It is used in designing of laboratory thermometers.
:
D
Archimedes principle states that the upward buoyant force that is exerted on an object which is immersed in a fluid, whether fully or partially submerged, is equal to the weight of the fluid that the object displaces.
It is used in the designing of ships, submarines. It is also used in lactometers and hydrometers as adulteration causes a change of density which can be easily identified using these tools. Archimedes principle has nothing to deal with the designing of thermometers.
:
D
Archimedes principle states that the upward buoyant force that is exerted on an object which is immersed in a fluid, whether fully or partially submerged, is equal to the weight of the fluid that the object displaces.
It is used in the designing of ships, submarines. It is also used in lactometers and hydrometers as adulteration causes a change of density which can be easily identified using these tools. Archimedes principle has nothing to deal with the designing of thermometers.
Answer: Option D. -> weight decreases
:
D
The value of acceleration due to gravity is maximum at the surface of the earth. It decreases with increase in height from the surface. It also decreases with increase in depth from the surface. Hence, it is lower in the mine.
Since weight is the product of mass and acceleration due to gravity, it also decreases in a mine.
:
D
The value of acceleration due to gravity is maximum at the surface of the earth. It decreases with increase in height from the surface. It also decreases with increase in depth from the surface. Hence, it is lower in the mine.
Since weight is the product of mass and acceleration due to gravity, it also decreases in a mine.
Answer: Option A. -> 49 N
:
A
Given, mass of a body m=5kg and acceleration due to gravity g=9.8ms−2.
As we know, weight,
W=m×g=5×9.8=49N
Therefore, weight on the surface of the earth would be 49N.
:
A
Given, mass of a body m=5kg and acceleration due to gravity g=9.8ms−2.
As we know, weight,
W=m×g=5×9.8=49N
Therefore, weight on the surface of the earth would be 49N.
Answer: Option C. -> F∝1R2
:
C
According to the Universal law of gravitation, the gravitational force between twobodies is directly proportional to product of their masses and inversely proportional to the square of the distance between them. Thus, in this case, the gravitational force between the point masses isinversely proportional to R2.
Hence, F∝1R2
:
C
According to the Universal law of gravitation, the gravitational force between twobodies is directly proportional to product of their masses and inversely proportional to the square of the distance between them. Thus, in this case, the gravitational force between the point masses isinversely proportional to R2.
Hence, F∝1R2
Answer: Option A. -> Pa and N
:
A
We know , Pressure =ForceArea
So,unit of pressure isNm−2 which is called Pascal (Pa).
Sincethrust is the perpendicular force acting on a body, its unit is Newton (N).
:
A
We know , Pressure =ForceArea
So,unit of pressure isNm−2 which is called Pascal (Pa).
Sincethrust is the perpendicular force acting on a body, its unit is Newton (N).
Answer: Option B. -> False
:
B
Archimedes' principle states that the buoyant force exerted on a body submerged in a liquid is equal to the weight of the liquid displaced. Also, the force exerted on a body cannot be compared with a volume, as these are two different physical quantities.
:
B
Archimedes' principle states that the buoyant force exerted on a body submerged in a liquid is equal to the weight of the liquid displaced. Also, the force exerted on a body cannot be compared with a volume, as these are two different physical quantities.
Answer: Option A. -> 15 kgf
:
A
Combined weight of astronaut and his space suit on Earth =60+30=90kgf
Since, Moon's gravity is one-sixth of that ofthe Earth, the weight of the object on Moon is one-sixth of that on the Earth.
∴ the combined weight of the astronaut and his space suit on Moon is 906=15kgf
:
A
Combined weight of astronaut and his space suit on Earth =60+30=90kgf
Since, Moon's gravity is one-sixth of that ofthe Earth, the weight of the object on Moon is one-sixth of that on the Earth.
∴ the combined weight of the astronaut and his space suit on Moon is 906=15kgf
Answer: Option D. -> All bodies in the universe
:
D
According to the law of gravitation, the force of gravitation between two bodiesis directly proportional to theirmasses and is inversely proportional to the square of the distance between them. Newton's law of gravitation is applicable to all the bodies in the universe. It remains valid everywhere in the universe.
:
D
According to the law of gravitation, the force of gravitation between two bodiesis directly proportional to theirmasses and is inversely proportional to the square of the distance between them. Newton's law of gravitation is applicable to all the bodies in the universe. It remains valid everywhere in the universe.