4th Grade > Mathematics
FACTORS AND MULTIPLES MCQs
Total Questions : 40
| Page 2 of 4 pages
Answer: Option B. -> 1
:
B
The greatest number that can divide 2, 3 and 6 exactly is their HCF.
Factors of 2: 1, and 2
Factors of 3: 1, and 3
Factors of 6: 1, 2, 3, and 6
So, the common factor is 1 which is also the HCF.
:
B
The greatest number that can divide 2, 3 and 6 exactly is their HCF.
Factors of 2: 1, and 2
Factors of 3: 1, and 3
Factors of 6: 1, 2, 3, and 6
So, the common factor is 1 which is also the HCF.
Answer: Option B. -> 15
:
B
Factors of 3: 1, 3
Factors of 5: 1, 5
3 and 5 are co-prime numbers because 1 is their only common factor.
LCM of co-prime numbers is equal to the product of the numbers.
So,
LCM of 3 , 5=3×5=15
:
B
Factors of 3: 1, 3
Factors of 5: 1, 5
3 and 5 are co-prime numbers because 1 is their only common factor.
LCM of co-prime numbers is equal to the product of the numbers.
So,
LCM of 3 , 5=3×5=15
:
1 is an unique number. It is neither a prime number nor a composite number.
1 is the only number that does not have two factors.
Answer: Option A. -> 2
:
A
Factors of 6: 1, 2, 3, 6
Factors of 4: 1, 2, 4
Common factors : 1 ,2
Hence, 6 and 4 have 2 common factors.
:
A
Factors of 6: 1, 2, 3, 6
Factors of 4: 1, 2, 4
Common factors : 1 ,2
Hence, 6 and 4 have 2 common factors.
Answer: Option A. -> 24
:
A
The least number which is exactly divisible by 6, 12, 24 is the LCM of the 3 numbers.
26,12,2423,6,1223,3,633,3,31,1,1
LCM of 6, 12 and 24
=2×2×2×3=24
:
A
The least number which is exactly divisible by 6, 12, 24 is the LCM of the 3 numbers.
26,12,2423,6,1223,3,633,3,31,1,1
LCM of 6, 12 and 24
=2×2×2×3=24
Answer: Option A. -> Number itself
:
A
The largest factor of a number is the "number itself".
For example, the highest factor of 48 is 48.
The lowest factor of any number is 1.
:
A
The largest factor of a number is the "number itself".
For example, the highest factor of 48 is 48.
The lowest factor of any number is 1.
Answer: Option B. -> 24 cm
:
B
To find the shortest length that can be measured exactly by using each one of these rods, we need to find the LCM of their lengths.
26,4,823,2,423,1,233,1,11,1,1
LCM =2×2×2×3=24cm
Therefore, 24cm is the shortest length that can be measured exactly by each one of these rods.
:
B
To find the shortest length that can be measured exactly by using each one of these rods, we need to find the LCM of their lengths.
26,4,823,2,423,1,233,1,11,1,1
LCM =2×2×2×3=24cm
Therefore, 24cm is the shortest length that can be measured exactly by each one of these rods.
Answer: Option D. -> 100
:
D
Using the prime factorization method:
225,50,100525,25,5055,5,1021,1,21,1,1
LCM of25, 50 and 100 =2×5×5×2=100
:
D
Using the prime factorization method:
225,50,100525,25,5055,5,1021,1,21,1,1
LCM of25, 50 and 100 =2×5×5×2=100
Answer: Option D. -> Infinite
:
D
To get multiples of any number, we multiply counting numbers with that number.
Since there are infinite counting numbers, multiples of any number are also infinite.
:
D
To get multiples of any number, we multiply counting numbers with that number.
Since there are infinite counting numbers, multiples of any number are also infinite.
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