option (c) Total daily consumption of Captain cook can be found as follows
for bread the consumption = 30 X (5/10) X (40/100)= 6

Similarly for the other products (6 + 4.5 + 20.25 + 22.5 + 0) = 53.25 m³

While total daily consumption of Trupti+ flour was = 9 + 5.5 + 24.75 + 7.5 + 20 = 66.75 m³

The ratio of volume of Captain cook flour to that of Trupti flour consumed daily is  53.25/66.75 = 0.7

option (a) He increased the sugar content in pastries from 21 to 42 and so the total sugar requirement increased from 55 to 55 + 21 = 76 m³. Further flour content in pastries reduced by 2/3 * 18 = 12m³. Thus flour content became 93 – 12 = 81. Therefore now the total volume of daily consumption of sugar and flour respectively, in m³ becomes 76 and 81 respectively.

option (a)

From (1), we know that 180 students failed in all five subjects. So if we take the second row from the top then in all the papers the absolute number is 180, the % value can change depending upon the number of students who failed in that paper. So in Signal, total number of students = 900. Number of students who failed in exactly 5 = 180. So % = (180/900)* 100 = 20%. So, left percentage = 100 – (20 + 20 + 10 + 30) = 20%.

Hence, the number of students who failed in exactly 2 = 20% of 900 = 180.

option (c) Percentage of total supermix that was used for pastries is = [51/(30+28+51+72+38)*100] = [51/219*100] = 23%

option (b) Total consumption/day of Captain cook flour was (6 + 4.5 + 20.25 + 22.5 + 0) = 53.25 m³

% of exactly two in electronics is 10%. So 90 students who failed in electronics failed in exactly two papers. Similarly 90 students who failed in VLSI, failed in exactly two papers.So at most 90 failed in Electronics and VLSI. Option d

Suppose total number of students who failed in C++ = x. 20% of the students failed in exactly 4 subjects, then % of students who failed in exactly 5 subject = 30%. Now 30% of x = 180. So x = 600. So 600 students failed in C++. option c

Number of face-offs= 28. More than 14 need to be revelations.

Inshatullah can win all the 7 games. The remaining 7 members can win 3 games each totaling to >14 revelations. Answer is option (a)

Total number of face-offs are ⁸C₂=28. If the highest number of wins in module 1 is 7, then the other person advancing to the next round can win 3 face-offs and qualify. The remaining people can also win 3 face-offs each; totaling to 7+(7*3) =28 face-offs. If 7 members win 2 face-offs, then the total number of points do not add up to 28. Hence, answer is option (c)

option d