Data Handling(8th Grade > Mathematics ) Questions and answers for exam Preparation

8th Grade > Mathematics

DATA HANDLING MCQs

Total Questions : 57 | Page 3 of 6 pages

Question 21. A bag contains 1 red ball 1 green ball 2 blue balls and 1 black ball. If a ball is drawn out of the bag, the probability of getting a ball of each colour is equally likely.

True
False
16
0

Discuss Question

Answer: Option B. -> False
:
B

Probability = \frac{no. of favorable outcomes}{total no. of outcomes}

Therefore, the probability of getting a blue ball

= \frac{2}{5}

While the probability of getting a black ball

= \frac{1}{5}

Also, the probabiltiy of getting a green ball

= \frac{1}{5}

So the eventsarenot equally likely.

Question 22. If 1100 people like playing cricket, then what is the total number of people who took the survey? Following pie chart shows the percentage of people playing some game.

2000
1000
5000
None of these

Discuss Question

Answer: Option A. -> 2000
:
A
Let the total number of people surveyed is x.
Given that 55% of all the people surveyed play cricket.
So, 55% of x= 1100.

\frac{55 x}{100} = 1100

x = \frac{1100 \times 100}{55}

x = 2000

Hence there are 2000 people were surveyed..

Question 23. There are 216 workers in a factory out of which 75 are laborers. What would be the central angle of the sector representing laborers in a pie chart?

360∘
180∘
125∘
120∘

Discuss Question

Answer: Option C. -> 125∘
:
C
Central angle

= \frac{no. of laborers}{no. of workers} \times 360^{\circ}

= \frac{75}{216} \times 360^{\circ}

= 125^{\circ}

Question 24. The histogram gives the information about the number of literate males along with their age. Below the age of 30, how many males are literate?

1400
1300
1900
900

Discuss Question

Answer: Option D. -> 900
:
D
Below the age of 30, the following the frequencies in the different age groups:
10-20 years: 300 literate males
20-30 years: 600 literate males
Therefore, the required number is 300+600 = 900

Question 25. If a die is thrown, what is the probability of getting a multiple of 3?

Discuss Question

Answer: Option A. -> 13
:
A
If a die is thrown then the outcomes which are multiple of 3 are 3 and 6.
So the probability of getting 3 and 6

= \frac{Outcomes of interest}{Total number of outcomes}

= \frac{2}{6}

\frac{1}{3}

Question 26. A set of numerical facts, collected with a definite object in view, is known as

Range
Frequency
Data
Tally marks

Discuss Question

Answer: Option C. -> Data
:
C
A set of numerical facts, collected with a definite object in view, is known as data.

Question 27. The number of students who have scored between 80-90 marks is
___

Discuss Question

:
From the given histogram, it can be observed that 2 divisions on the y-axis correspond to 1 student.
Hence, the number of students scoring between 80-90 = 13

Question 28.

A bag contains 1 red ball, 1 green ball, 2 blue balls and 1 black ball. What is the probability of getting a white ball?

0
$\frac{1}{5}$
$\frac{1}{4}$
1

Discuss Question

Answer: Option A. -> 0
:
A

The probability of getting a white ball is 0 as there are 0 white balls.

Question 29.

A coin is thrown and it lands on a chess board. Find the probability of it landing on a white square if it falls exactly inside a square.

$\frac{1}{64}$
$\frac{1}{32}$
$\frac{1}{4}$
$\frac{1}{2}$

Discuss Question

Answer: Option D. ->

\frac{1}{2}

:
D

$Probability = \frac{Number of favourable outcomes}{Total Number of outcomes}$
Number of white squares (favourable outcomes) = 32
Total number of squares or outcomes = 64
So probability of coin falling in a white square
$= \frac{Number of white squares}{Total number of squares}$
$= \frac{32}{64}$
$= \frac{1}{2}$

Question 30.

In a game of cards, 7 cards are taken and numbered 1 to 7. The probability of getting an even number and the probability of getting an odd number are equal.

True
False
$\frac{1}{4}$
$\frac{1}{2}$

Discuss Question

Answer: Option B. -> False
:
B

The cards are numbered as 1,2,3,4,5,6,7
Total number of outcomes = 7
Number of odd numbers (favourable outcomes) = 4
Number of even numbers (favourable outcomes) = 3
$Probability = \frac{Number of favourable outcomes}{Total Number of outcomes}$
Probability of getting odd number
$= \frac{Number of odd numbered cards}{Total number of cards}$ ;
$= \frac{4}{7}$
Probability of getting even number
$= \frac{Number of even numbered cards}{Total number of cards}$
$= \frac{3}{7}$
Probabilities are different. Hence, the statement is false.