MCQs
Total Questions : 62
| Page 6 of 7 pages
Answer: Option C. -> 2300-6000
Answer: (c).2300-6000
Answer: (c).2300-6000
Question 52. A hot plate of 15 cm² area maintained at 200 degree celsius is exposed to still air at 30 degree Celsius temperature. When the smaller side of the plate is held vertical, convective heat transfer rate is 15 per cent higher than bigger side of the plate is held vertical. Find size of the plate. The appropriate correlation for the convection coefficient is
Nu = 0.60 (Gr Pr)^0.25
Nu = 0.60 (Gr Pr)^0.25
Answer: Option A. -> l = 5.123 cm and b = 2.928 cm
Answer: (a).l = 5.123 cm and b = 2.928 cm
Answer: (a).l = 5.123 cm and b = 2.928 cm
Answer: Option C. -> Convection
Answer: (c).Convection
Answer: (c).Convection
Answer: Option B. -> Fluid passing through the tubes of a condenser and other heat exchange equipment
Answer: (b).Fluid passing through the tubes of a condenser and other heat exchange equipment
Answer: (b).Fluid passing through the tubes of a condenser and other heat exchange equipment
Answer: Option D. -> Cooling of billets in atmosphere
Answer: (d).Cooling of billets in atmosphere
Answer: (d).Cooling of billets in atmosphere
Answer: Option B. -> 3
Answer: (b).3
Answer: (b).3
Answer: Option A. -> Intense stirring by an external agency
Answer: (a).Intense stirring by an external agency
Answer: (a).Intense stirring by an external agency
Answer: Option C. -> 0.6
Answer: (c).0.6
Answer: (c).0.6
Question 59. Air at atmospheric pressure and 20 degree Celsius flows with 6 m/s velocity through main trunck duct of air conditioning system. The duct is rectangular in cross-section and measures 40 cm by 80 cm. Determine heat loss per meter length of duct corresponding to unit temperature difference. The relevant thermos-physical properties of air are
v = 15 * 10¯⁶ m²/s
α = 7.7 * 10¯² m²/hr
k = 0.026 W/m degree
v = 15 * 10¯⁶ m²/s
α = 7.7 * 10¯² m²/hr
k = 0.026 W/m degree
Answer: Option B. -> 42.768 W
Answer: (b).42.768 W
Answer: (b).42.768 W
Answer: Option D. -> Nu = 0.664 (Re)^0.5 (Pr)^0.33
Answer: (d).Nu = 0.664 (Re)^0.5 (Pr)^0.33
Answer: (d).Nu = 0.664 (Re)^0.5 (Pr)^0.33