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MCQs

Communication Systems(12th Grade -Physics)

Total Questions : 167 | Page 2 of 17 pages
Question 11. A 500 Hz modulating voltage fed into an FM generator produces a frequency deviation of 2.25 kHz. If amplitude of the voltage is kept constant but frequency is raised to 6 kHz then the new deviation will be
  1.    4.5 kHz
  2.    54 kHz
  3.    27 kHz
  4.    15 kHz
  5.    The frequency of modulated wave varies as frequency of carrier wave
 Discuss Question
Answer: Option B. -> 54 kHz
:
B
mf = δfm=2250500 = 4.5
New deviation = 2(mffm) = 2 × 4.5 × 6 = 54 kHz.
Question 12. Broadcasting antennas are generally 
  1.    Omni directional type
  2.    Vertical type
  3.    Horizontal type
  4.    None of these
 Discuss Question
Answer: Option B. -> Vertical type
:
B
Broadcasting antennas are generally vertical type.
Question 13. In AM, the centpercent modulation is achieved when
  1.    Carrier amplitude = signal amplitude
  2.    Carrier amplitude−1 = signal amplitude  
  3.    Carrier frequency = signal frequency
  4.    Carrier frequency−1 = signal frequency
  5.    The frequency of modulated wave varies as frequency of carrier wave
 Discuss Question
Answer: Option A. -> Carrier amplitude = signal amplitude
:
A
When signal amplitude is qual to the carrier amplitude, the amplitude of carrier ware varies between 2A and zero.
In AM, The Centpercent Modulation Is Achieved When
ma=AmplitudechargeofcarrierAmplitudeofnormalcarrier=2AAA×100 = 100%
Question 14. For television broadcasting, the frequency employed is normally
  1.    30-300 MHz
  2.    30-300 GHz
  3.    30-300 KHz
  4.    30-300 Hz
 Discuss Question
Answer: Option A. -> 30-300 MHz
:
A
VHF (Very High Frequency) band having frequency range 30MHzto 300MHzis typically used for TV and radar transmission.
Question 15. An oscillator is producing FM waves of frequency 2 kHz with a variation of 10 kHz. What is the modulating index
  1.    0.20
  2.    5.0
  3.    0.67
  4.    1.5
 Discuss Question
Answer: Option B. -> 5.0
:
B
The formula for modulation index is given by
mf=δvm=FrequencyvariationModulatingfrequency=10×1032×103=5
Question 16. A transmitter supplies 9 kW to the aerial when unmodulated. The power radiated when modulated to 40% is
  1.    5 kW
  2.    9.72 kW
  3.    10 kW
  4.    12 kW
  5.    The frequency of modulated wave varies as frequency of carrier wave
 Discuss Question
Answer: Option B. -> 9.72 kW
:
B
Pt = Pc[1+m22] = 9 [1 + (0.4)22]
= 9 [1 + 0.162] ( m = 40 % = 0.4)
= 9 (1.08) = 9.72 kW
Question 17. The audio signal used to modulate 60 sin 2π106t is 15sin 300πt. The depth of modulation is
  1.    50%
  2.    40%
  3.    25%
  4.    15%
  5.    The frequency of modulated wave varies as frequency of carrier wave
 Discuss Question
Answer: Option C. -> 25%
:
C
ma=EmEc=1560×100 = 25 %
Question 18. Read the assertion and reason carefully to mark the correct option out of the options given below:
Assertion :The electromagnetic waves of shorter wavelength can travel longer distances on earth's surface than those of longer wavelengths.
Reason : Shorter the wavelength, the larger is the velocity of wave propagation.
  1.    Both assertion and reason are true and the reason is the correct explanation of the assertion.
  2.    Both assertion and reason are true but reason is not the correct explanation of the assertion.
  3.    Assertion is true but reason is false.
  4.    The assertion and reason both are false.
  5.    If assertion is false but reason is true.
 Discuss Question
Answer: Option C. -> Assertion is true but reason is false.
:
C
The electromagnetic waves of shorter wavelength do not suffer much diffraction from the obstacles of earth's atmosphere so they can travel long distance.
Also, shorter the wavelength, shorter is the velocity of wave propagation.
Question 19. In which of the following remote sensing technique is not used
  1.    Forest density
  2.    Pollution
  3.    Wetland mapping
  4.    Medical treatment
 Discuss Question
Answer: Option D. -> Medical treatment
:
D
Remote sensing is the technique to collect information about an object in respect of its size, colour, nature, location, temperatureetc.without physically touching it. There are some areas or location which are inaccessible. So to explore these areas or locations, a technique known as remote sensing is used. Remote sensing is done through a satellite.
Question 20. The bit rate for a signal, which has a sampling rate of 8 kHz and where 16 quantisation levels have been used is
  1.    32000 bits/sec
  2.    16000 bits/sec
  3.    64000 bits/sec
  4.    72000 bits/sec
  5.    If assertion is false but reason is true.
 Discuss Question
Answer: Option A. -> 32000 bits/sec
:
A
If n is the number of bits per sample, then number of quantisation level = 2n
Since the number of quantisation level is 16
2n=16 n = 4
bit rate = sampling rate × no.of bits per sample
= 8000 × 4 = 32,000 bits/sec

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