12th Grade > Physics
ATOMS AND NUCLEI MCQs
Atoms, Nuclei (12th Grade)
Total Questions : 60
| Page 3 of 6 pages
Answer: Option D. -> 8 and 6
:
D
nα=A−A′4=200−1684=8
nβ=2nα−Z+Z′=2×8−90+80=6
:
D
nα=A−A′4=200−1684=8
nβ=2nα−Z+Z′=2×8−90+80=6
Answer: Option A. -> 6 : 10
:
A
By using r∝A13⇒r1r2=(A1A2)13=(27125)13=35=610
:
A
By using r∝A13⇒r1r2=(A1A2)13=(27125)13=35=610
Answer: Option B. -> β− emission
:
B
β - decay from nuclei based on this process only.
:
B
β - decay from nuclei based on this process only.
Answer: Option D. -> 7.5×106
:
D
E=Δm.c2⇒E=0.31000×(3×108)2=2.7×1013J
=2.7×10133.6×106=7.5×106kWh.
:
D
E=Δm.c2⇒E=0.31000×(3×108)2=2.7×1013J
=2.7×10133.6×106=7.5×106kWh.
Answer: Option B. -> In 12 minutes
:
B
substance reduces to 10 gm (i.e. becomes half in 4 min). So T12=4min. Again M=M0(12)t/T1/2
⇒10=80(12)t4⇒18=(12)3(12)t4⇒t=12min.
:
B
substance reduces to 10 gm (i.e. becomes half in 4 min). So T12=4min. Again M=M0(12)t/T1/2
⇒10=80(12)t4⇒18=(12)3(12)t4⇒t=12min.
Answer: Option B. -> 80 s−1
:
B
A=A0(12)t/T1/2⇒5=A0(12)2×6030=A016⇒A0=80sec−1
:
B
A=A0(12)t/T1/2⇒5=A0(12)2×6030=A016⇒A0=80sec−1
Answer: Option C. -> 12 hour
:
C
N=N0(12)t/T1/2⇒1=16(12)2/T1/2⇒T12=12hour
:
C
N=N0(12)t/T1/2⇒1=16(12)2/T1/2⇒T12=12hour
Answer: Option C. -> 126.15 MeV
:
C
Radius of each nucleus R=R0(A)13=1.2(64)13=4.8fm
Distance between two nuclei (r) = 2R
So potential energy U=k.q2r=9×109×(1.6×10−19×29)22×4.8×10−15×1.6×10−13=126.15MeV.
:
C
Radius of each nucleus R=R0(A)13=1.2(64)13=4.8fm
Distance between two nuclei (r) = 2R
So potential energy U=k.q2r=9×109×(1.6×10−19×29)22×4.8×10−15×1.6×10−13=126.15MeV.
Answer: Option A. -> 14.4 hours
:
A
Mean life =Halflife0.6931=100.6931=14.4hours
:
A
Mean life =Halflife0.6931=100.6931=14.4hours