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9th Grade > Chemistry

ATOMS AND MOLECULES MCQs

Total Questions : 85 | Page 8 of 9 pages
Question 71.


What is the full form of IUPAC?  [1 MARK]


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Answer: Option A. ->
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Expansion: 1 Mark
IUPAC stands for International Union of Pure and Applied Chemistry. It is an international scientific organisation which approves names of elements, symbols and units.


Question 72.


Define atomicity. What will be the atomicity of ozone and ammonia?  [2 MARKS]
 


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Each point: 1 Mark
1. Atomicity is the total number of atoms present in one molecule of an element or a substance.
2. a. The chemical compound ozone is composed of 3 oxygen atoms. Therefore atomicity is three.
    b. The chemical formula of ammonia is NH3 in which there are 3 Hydrogen atoms and 1 Nitrogen atom. Therefore the atomicity is four.


Question 73.


Why was carbon-12 preferred over oxygen-16 to be chosen as the standard reference for measuring atomic masses?   [2 MARKS]


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Each point : 1 Mark
1. Oxygen is a mixture of O-16 , O-17 and O-18 isotopes, which gives the average mass if oxygen is taken as the standard.
2. C-12 is the most abundant isotope of carbon which constitutes 98.9% of available isotopes of carbon.
So it was better to choose Carbon-12 isotope as the standard.


Question 74.


Which has more number of atoms, 100 grams of sodium or 100 grams of iron (given, atomic mass of Na = 23 u, Fe = 56 u)?  [3 MARKS]
 


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Each point: 1.5 Marks
1. Atomic mass of Na = 23 u (Given)


Then, gram atomic mass of Na = 23 g


Now, 23 g of Na contains = 6.022 x 1023 g number of atoms


Thus, 100 g of Na contains =   6.022×102323×100 number of atoms


= 2.6182 x 1024 number of atoms.



2. Again, atomic mass of Fe = 56 u (Given)


Then, gram atomic mass of Fe = 56 g


Now, 56 g of Fe contains = 6.022 x 1023 g number of atoms


Thus, 100 g of Fe contains = 6.022×102356×100 number of atoms


= 1.0753 x 1024 number of atoms.


Question 75.


What is the mass of:  [3 MARKS]


1.  0.2 mole of elemental oxygen atom
2.  0.5 mole of water molecules

3.  2 mole of cabon dioxide


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Each point: 1 Mark
1. Mass of one mole of elemental oxygen atom = 16 g
Then, mass of 0.2 mole of oxygen atoms = 0.2 x 16g = 3.2 g


2. Mass of one mole of water molecule = (2 x 1 g)+ 16 g =18 g
Then, mass of 0.5 mole of water molecules = 0.5 x 18 g = 9 g


3. Mass of one mole of carbon dioxide molecule = 12 g + (2 x 16 g) = 44 g
Then, mass of two mole of carbon dioxide molecule = 2 x 44 g = 88 g
Question 76.


State the two laws of chemical combination.  [2 MARKS]
 


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Statement : 1 Mark each
The two laws of chemical combination are
1. Law of conservation of mass: 
The law of conservation of mass states that mass in an isolated system is neither created nor destroyed by chemical reactions or physical transformations. According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.
2. Law of definite proportions:
The law of definite proportions, also called Proust's law or the law of definite composition, or law of constant composition states that a given chemical compound always contains its component elements in fixed ratio (by weight) and does not depend on its source and method of preparation.


Question 77.


Find the formula of ammonium sulphate.   [3 MARKS]


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Each point: 1 Mark
1. Charge on ammonium(NH4+) is +1


2. Charge on sulphate(SO42) is -2


3. By cross over charges to balance charges


(NH4)2SO4.


Question 78.


Find the chemical formula of carbon tetrachloride.   [3 MARKS]


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Concept : 1 Mark
Process : 1 Mark 
Result : 1 Mark
Carbon and chlorine will combine in such a manner that their valencies should get satisfied. 
Valency of Carbon = 4
Valency of Chlorine = 1
To satisfy the valency of Carbon, 4 chlorine atoms each having a valency of 1 would be required. Hence, the formula is CCl4


Question 79.


Find the chemical formula of aluminum chloride.  [2 MARKS]
 


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Each step: 1 Mark
1. Valency of  aluminium = 3


2. Valency of chlorine =1


3. By crossing over the valencies we have AlCl3.


Question 80.


What is meant by chemical formula? Calculate the number of aluminium ions present in 0.051 g of aluminium oxide.
(Hint: The mass of an ion is the same as that of an atom of the same element. Atomic mass of Al = 27 u)
[5 MARKS]


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Answer: Option A. ->
:

Each point: 1 Mark
1. The chemical formula of a compound is a symbolic representation of its composition.


2. Mole of aluminium oxide (Al2O3) = 2 x 27 + 3 x 16


= 102 g


3. i.e., 102 g of Al2O3= 6.022 x 1023 molecules of Al2O3


4. Then, 0.051 g of Al2O3 contains = 6.022×1023102×0.051 molecules


= 3.011 x 1020 molecules of Al2O3


5. The number of aluminium ions ((Al3+) present in one molecule of aluminium oxide is 2.


Therefore, the number of aluminium ions (Al3+) present in 3.011 x 1020 molecules (0.051 g ) of aluminium oxide (Al2O3) = 2 x 3.011 x 1020


= 6.022 x 1020


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