Arithmetic(Exams > Cat > Quantitaitve Aptitude ) Questions and answers for exam Preparation

Exams > Cat > Quantitaitve Aptitude

ARITHMETIC MCQs

Total Questions : 147 | Page 11 of 15 pages

The petrol consumption rate of a new model car 'Palto' depends on its speed and may be described by the graph below.

Manasa would like to minimize the fuel consumption for the trip by driving at the appropriate speed. How should she change the speed?

Increase the speed
Decrease the speed
Maintain the speed at 60 km/hr
Cannot be determined

Discuss Question

Answer: Option B. -> Decrease the speed
:
B

(b) At a speed of 40 km/hr,60 km/hr, and 80 km/hr distance travelled in 1 litre of petrol.
$= \frac{40}{2.5} = 16 k m, \frac{60}{4} = 15 k m, \frac{80}{7.9} = 10.1 k m .$ respectively.
Hence at lower speed fuel consumption is less.Hence in order to minimize the fuel consumption, the speed should be decreased.

Question 102.

The petrol consumption rate of a new model car 'Palto' depends on its speed and may be described by the graph below.

Manasa makes a 200 km trip from Mumbai to Pune at a steady speed of 60 km per hour. What is the amount of petrol consumed for the journey?

12.5 litres
13.33 litres
16 litres
19.75 litres

Discuss Question

Answer: Option B. -> 13.33 litres
:
B

Fuel consumption is given in litre per hour. It is, therefore, clear from the graph that in travelling 60 km fuel consumption is 4 litres. Hence in travelling 200 km fuel consumption will be = 13.33 litres

Question 103.

Arun invests in bonds worth Rs. 40000 and he receives a $15 %$ interest per annum. How much money should he invest in bonds that give $10 %$ per annum so that he gains overall $12 %$ per annum?

50000
65000
60000
62500

Discuss Question

Answer: Option C. -> 60000
:
C

Using alligation

He should invest in the ratio 2:3

He should invest 60000

Question 104.

In a company, there are initially ‘n’ employees. First $p %$ employees were hired and after a month $q %$ of the employees were fired. This again made the number of employees in the company as ‘n’. Find the value of p – q.

$\frac{p q}{100}$
pq
$\frac{p + q}{100}$
$\frac{2 n}{p}$

Discuss Question

Answer: Option A. ->

\frac{p q}{100}

:
A

$n (1 + \frac{p}{100}) (1 - \frac{q}{100}) = n / n (1 + \frac{p}{100} - \frac{q}{100} - \frac{p q}{100^{2}}) / n 1 + \frac{p}{100} - \frac{q}{100} - \frac{p q}{100^{2}} = 1 \frac{p}{100} - \frac{q}{100} = \frac{p q}{100^{2}} \Rightarrow p - q = \frac{p q}{100}$

Question 105.

In an automated plant assembly line, the rate of rejection of components was $10 %$ on July 1st and $6 %$ on July 2nd. The combined rate of rejection for the two days was $9 %$ . The ratio of production volumes on July 1st and on July 2nd is

2: 1
3: 2
3: 1
2: 5

Discuss Question

Answer: Option C. -> 3: 1
:
C

Use alligation

Answer is option (c)

Question 106.

In a factory, a part of the 1500 employees reported for the work while others were on leave. The next day, $4 %$ of the workers who were on leave on the first day reported for the work and $6 %$ of the workers who came on the $1^{s t}$ day joined the strike. If the number of workers on leave on both days were the same, then how many workers were on leave?

Discuss Question

Answer: Option D. -> 900
:
D

Let workers on leave: present workers = x: y.

0.04x come to work and 0.06y take leave on the second day. As there will be no difference in value of x and y after this exchange: 0.04x = 0.06y
x: y = 6: 4 or 3: 2.

Number of workers on leave $= (\frac{3}{5}) \times 1500 = 900$

Hence option (d)

Alternatively, go from answer options

$2^{n d}$ day number joining and number on leave should be the same

This happens only when the number of leave = 900

$2^{n d}$ day = $4 % o f 900 - 6 % o f 600 = 0$ . Option (d)

Question 107.

When the air-conditioner is on, a typist can type X pages per hour. However, when the air-conditioner is off, she can type at $65 %$ of the earlier efficiency (when the air-conditioner is on). How many hours would she take to type out 575 pages when the air-conditioner is off?

375.4 X
$884.6 X^{- 1}$
$454.3 X^{- 1}$
None of these

Discuss Question

Answer: Option B. ->

884.6 X^{- 1}

:
B

Let X=100, Then when AC is off, speed = 65 pages per hour.

Thus to type 575 pages, she takes $\frac{575}{65} = 8.84$ pages per hour. Answer is option (b

Alternatively:
When the air-conditioner is off, 0.65X pages are typed per hour. 575 pages will be typed in

$\frac{575}{0.65 X} = 884.6 X^{- 1}$

Question 108.

When Sunil and Tanuj went for shopping initially Sunil had twice the money than Tanuj. They together bought things amounting to Rs.250. Out of which Tanuj’s share was $60 %$ . At the end Sunil was left with thrice the amount that Tanuj had. What was the amount with Tanuj at the beginning___

Discuss Question

Answer: Option B. ->

884.6 X^{- 1}

Initial money with Sunil = s and Tanuj = t

Purchases made by them = Rs. 250

Tanuj’s purchase = $60 %$ of Rs. 250 = Rs. 150

Sunil’s purchase = Rs. 250 – Rs. 150 = Rs. 100

So, money left in the end (s – 100) and (t – 150)

Given s = 2t and (s – 100) = 3 (t – 150)

Solving we get t = 350.

Question 109.

Raman plans to sell his goods at a loss of $8 %$ but uses weights of 900 grams in place of a kg weight. Find his real loss or gain percent?

$3 %$
$20 %$
$10 %$
$2.22 %$

Discuss Question

Answer: Option D. ->

2.22 %

:
D

Raman plans to sell his goods at a loss of $8 %$ . Therefore, Selling Price $= (100 - 8) %$ of CP = 0.92 CP. But, when he uses weights that measure only 900 grams while he claims to measure 1 kg.Hence,
CP of 900gms $= 0.90 \times O r i g i n a l C P$
So, he is selling goods worth 0.90 CP at 0.92 CP

Therefore, he makes a profit of 0.02 CP on his cost of 0.9 CP profit $% = 2.22 %$

Question 110.

There is an alloy (A) of silver and copper. A certain weight of this alloy is mixed with 15 kg of pure Silver and melted. The new alloy (B) contains $90 %$ of silver. If the alloy (A) is mixed with 10kg of a $90 %$ silver alloy, the new alloy (C) is found to contain $84 %$ silver. Find the percentage of silver in (A).