Area(Quantitative Aptitude ) Questions and answers for exam Preparation

Quantitative Aptitude

AREA MCQs

Areas

Total Questions : 2556 | Page 8 of 256 pages

A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?

Discuss Question

Answer: Option B. -> 3 m
- Area of the park = (60 x 40) m2 = 2400 m2.
Area of the lawn = 2109 m2.
Area of the crossroads = (2400 - 2109) m2 = 291 m2.
Let the width of the road be x metres. Then,
60x + 40x - x2 = 291
x2 - 100x + 291 = 0
(x - 97)(x - 3) = 0
x = 3.

Question 72.

The diagonal of the floor of a rectangular closet is 7 1/2 feet. The shorter side of the closet is 4 1/2 feet. What is the area of the closet in square feet?

Discuss Question

Answer: Option C. -> 27
- Other side = ( 15 ) 2 - ( 9 )2 2 2 ft = 225 - 81 4

Question 73.

A towel, when bleached, was found to have lost 20% of its length and 10% of its breadth. The percentage of decrease in area is:

Discuss Question

Answer: Option D. -> 28 %
- Let original length = a and original breadth = b.
Decrease in area = ab - 80 a x 90 b 100 100 = ab - 18 ab 25 = 7 ab. 25
Decrease % = 7 ab x 1 x 100 % = 28%. 25 ab

Question 74.

A man walked diagonally across a square lot. Approximately, what was the percent saved by not walking along the edges?

Discuss Question

Answer: Option C. -> 30
- Let the side of the square(ABCD) be x metres.
Then, AB + BC = 2x metres.
AC = 2x = (1.41x) m.
Saving on 2x metres = (0.59x) m.
Saving % = 0.59x x 100 % = 30% (approx.) 2x

Question 75.

The diagonal of a rectangle is 41 cm and its area is 20 sq. cm. The perimeter of the rectangle must be:

Discuss Question

Answer: Option B. -> 18 cm
- l2 + b2 = 41.

Also, lb = 20.
(l + b)2 = (l2 + b2) + 2lb = 41 + 40 = 81

(l + b) = 9.

Perimeter = 2(l + b) = 18 cm.

Question 76.

What is the least number of squares tiles required to pave the floor of a room 15 m 17 cm long and 9 m 2 cm broad?

Discuss Question

Answer: Option A. -> 814
- Length of largest tile = H.C.F. of 1517 cm and 902 cm = 41 cm.
Area of each tile = (41 x 41) cm2.
Required number of tiles = 1517 x 902 = 814. 41 x 41

Question 77.

The difference between the length and breadth of a rectangle is 23 m. If its perimeter is 206 m, then its area is:

Discuss Question

Answer: Option D. -> 2520 sq mt
- We have: (l - b) = 23 and 2(l + b) = 206 or (l + b) = 103.

Solving the two equations, we get: l = 63 and b = 40.
Area = (l x b) = (63 x 40) m2 = 2520 m2.

Question 78.

The length of a rectangle is halved, while its breadth is tripled. What is the percentage change in area?

Discuss Question

Answer: Option B. -> 50% increase
- Let original length = x and original breadth = y.
Original area = xy.
New length = x . 2
New breadth = 3y.
New area = x x 3y = 3 xy. 2 2
Increase % = 1 x y x 1 x 100 % = 50%. 2 xy

Question 79.

The length of a rectangular plot is 20 metres more than its breadth. If the cost of fencing the plot @ 26.50 per metre is Rs. 5300, what is the length of the plot in metres?

Discuss Question

Answer: Option D. -> Data inadequate
- Let breadth = x metres.

Then, length = (x + 20) metres.
Perimeter = 5300 m = 200 m. 26.50
2[(x + 20) + x] = 200
2x + 20 = 100
2x = 80
x = 40.

Hence, length = x + 20 = 60 m.

Question 80.

A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 680 sq. feet, how many feet of fencing will be required?

Discuss Question

Answer: Option D. -> 88
- We have: l = 20 ft and lb = 680 sq. ft.
So, b = 34 ft.

Length of fencing = (l + 2b) = (20 + 68) ft = 88 ft.