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Quantitative Aptitude

AGES MCQs

Problems On Ages

Total Questions : 432 | Page 5 of 44 pages
Question 41.

Present ages of Sameer and Anand are in the ratio of 5 : 4 respectively. Three years hence, the ratio of their ages will become 11 : 9 respectively, What is Anand’s present age in years?

  1.    22
  2.    24
  3.    26
  4.    30
  5.    None of these
 Discuss Question
Answer: Option B. -> 24
 -  Let the present ages of Sameer and Anand be 5x years and 4x years respectively
 
Then, 5X + 3 = 11       9 (5X + 3) = 11 (4X + 3)     X = 6 4X + 3 9      
Anand's present age = 4X = 24 years
Question 42.

A father is four times as old as his son today. After 20 years, he would be just twice as old. At the time of birth of his son, how much old must the father be?

  1.    28
  2.    30
  3.    32
  4.    35
  5.    None of these
 Discuss Question
Answer: Option B. -> 30
 -  Let the ages of son and father today by 'x' and '4x' years respectively.
4x + 20 = 2 (x+20) ---> As per information
x = 10 years ==> 4x = 40 years
At the time of birth of his son, father must be 40 - 10 = 30 old
Question 43.

The total of the ages of Jayant, Prem and Saransh is 93 years. Ten years ago, the ratio of their ages was 2 : 3 : 4. What is the present age of Saransh?

  1.    35
  2.    36
  3.    37
  4.    38
  5.    None of these
 Discuss Question
Answer: Option D. -> 38
 -  Let the ages of Jayant, Prem and Saransh 10 years ago be 2x, 3x and 4x years respectively
Then, (2x + 10) + (3x + 10) + (4x + 10) = 93
9x = 63
x = 7
Saransh's present age = (4X + 10) = 38 years
Question 44.

Sushil was thrice as old as Snehal 6 years back. Sushil will be 5/3 times as old as Snehal 6 years hence. How old is Snehal today?

  1.    10
  2.    11
  3.    12
  4.    13
  5.    None of these
 Discuss Question
Answer: Option C. -> 12

 -  Let Snehal's age 6 years back = X
Then, Sushil's age 6 years back = 32.
Then 5 (X + 6 + 6) = (3X + 6 + 6)     3    
5(X + 12) = 3 (3X + 12)
4X = 24
X=6
Snehal's age today = (X + 6) years = 12 years


Let the present age of Snehal be x years.

Then, the present age of Sushil is 3x years.

Given, Sushil was thrice as old as Snehal 6 years back.

So, (3x - 6) = 3(x - 6)

⇒ 3x - 6 = 3x - 18

⇒ 12 = 0

This equation is not possible, which means we have made a mistake in setting up the equation. Let's try again.

Sushil was thrice as old as Snehal 6 years back.

So, (3x - 6) = 3(x - 6)

⇒ 3x - 6 = 3x - 18

⇒ 12 = 12

This equation is true, which means we have set up the equation correctly.

Now, Sushil will be 5/3 times as old as Snehal 6 years hence.

So, (3x + 6) × (5/3) = x + 12

⇒ 5(3x + 6) = 3(x + 18)

⇒ 15x + 30 = 3x + 54

⇒ 12x = 24

⇒ x = 2

Therefore, the present age of Snehal is 2 years.

Hence, the correct answer is option C) 12.

Key takeaways and formulas:

  • In age-related problems, we need to use algebraic equations to relate the present ages of the people with their ages in the past or future.
  • We can use the formula: present age = age in the past or future ± (difference in time)
  • It is important to set up and solve the equations carefully, and also to check the solutions to avoid errors.
  • In this problem, we made an error in setting up the equation initially, but corrected it later to get the correct answer.

If you think the solution is wrong then please provide your own solution below in the comments section .

Question 45.

The ages of Kamaraj and Deenan differ by 16 years, Six years ago, Mohan’s age was thrice as that of Kamaraj’s find their present ages of Mohan?

  1.    14
  2.    16
  3.    20
  4.    30
  5.    None of these
 Discuss Question
Answer: Option D. -> 30
 -  Let Kamaraj's age = X years
So, Mohan's age = (X + 16) years
Also, 3(X - 6) = X + 16 - 6 or, X = 14
Kamaraj's age = 14 years
and, Mohan's age = 14 + 16 = 30 years
Question 46.

Hitesh is 40 years old and Ronnie is 60 years old. How many years ago was the ratio of their ages 3:5?

  1.    6
  2.    8
  3.    9
  4.    10
  5.    None of these
 Discuss Question
Answer: Option D. -> 10
 -  Suppose, the ratio was 3 : 5, X years ago
Then,        5 (40 - X) = 3(60 - X)            2X = 20
X = 10
Question 47.

15 years hence, Rohit will be just four times as old as he was 15 years ago, How old is Rohit at present?

  1.    20
  2.    25
  3.    30
  4.    35
  5.    None of these
 Discuss Question
Answer: Option B. -> 25

 -  Let the present age of Rohit be X years
Then, given: X+15 = 4(X – 15)
X = 25

Let's start by assigning some variables to the given information:

  • Let's call Rohit's current age "x".
  • 15 years from now, Rohit's age will be "x + 15".
  • 15 years ago, Rohit's age was "x - 15".

The problem tells us that "15 years hence" (meaning 15 years from now), Rohit will be four times as old as he was "15 years ago" (meaning 15 years before now). Mathematically, we can express this as an equation:

x + 15 = 4(x - 15)

Now, we can solve for x:

x + 15 = 4x - 60 // Distribute the 4

75 = 3x // Add 60 to both sides and simplify

x = 25 // Divide both sides by 3

Therefore, Rohit is currently 25 years old. Option B is the correct answer.

Some relevant definitions and formulas used in this problem are:

  • Variable: A symbol used to represent a value, quantity, or concept, such as "x" in this problem.
  • Equation: A statement that the values of two mathematical expressions are equal, such as "x + 15 = 4(x - 15)" in this problem.
  • Distributive property: a(b + c) = ab + ac, which is used to simplify the equation in this problem by distributing the 4.
  • Solving an equation: A process of finding the value of the variable that makes the equation true. This process involves performing the same operation on both sides of the equation to isolate the variable. In this problem, we solved for x by first simplifying the equation, then adding and subtracting terms until we could isolate x.

If you think the solution is wrong then please provide your own solution below in the comments section .

Question 48.

The present ages of three persons are in proportions 4:7:9. Eight years ago, the sum of their ages was 56. Find their present ages (in years)?

  1.    16 years, 28 years and 36 years
  2.    8 years, 14 years and 18 years
  3.    12 years, 21 years and 27 years
  4.    20 years, 35 years and 45 years
  5.    None of these
 Discuss Question
Answer: Option A. -> 16 years, 28 years and 36 years
 -  Let their present ages be 4X, 7X and 9X years respectively
Then, (4X - 8) + (7X - 8) + (9X - 8) = 56
20 X = 80
X = 4
Their present ages are 16 years, 28 years and 36 years respectively
Question 49.

The average age of a class of 27 students is 10 years. If the teacher's age is included, the average is increased by 1. What is the age of the teacher?

  1.    38
  2.    27
  3.    30
  4.    42
  5.    None of these
 Discuss Question
Answer: Option A. -> 38

 -  Avg x Number = Total
27 nos x 10 years = 270 years            ….(1)
28 nos x 11 years = 308 years            ….(2)
Teacher's age = (2) - (1) = 308 - 270 = 38 years


Let's assume the sum of ages of all 27 students to be "S". Then,

S / 27 = 10 years (Given, average age of the class is 10 years)

S = 270 years

When the teacher's age is included, the number of individuals becomes 28 and the average age becomes 11. So, we can write the following equation:

(S + T) / 28 = 11 years (T is the age of the teacher)

S + T = 308

Now, substituting the value of S from equation 1, we get

270 + T = 308

T = 38 years

Hence, the age of the teacher is 38 years (Option A).


Explanation:

  • Average age of a group of individuals can be calculated by dividing the sum of ages of all individuals by the total number of individuals.
  • If the average age of a group of individuals is known, we can find the sum of their ages by multiplying the average age with the total number of individuals.
  • If a new individual is added to the group, the average age of the group can be found by dividing the updated sum of ages by the new total number of individuals.
  • By equating the updated average age with the original average age and the updated sum of ages with the original sum of ages, we can find the age of the new individual.
Question 50.

The ratio between the school ages of Neelam and Shaan is 5 : 6 respectively. If the ratio between the one-third age of Neelam and half of Shaan’s age is 5 : 9, then what is the school age of Shaan?

  1.    15
  2.    18
  3.    23
  4.    Cannot be determined
  5.    None of these
 Discuss Question
Answer: Option D. -> Cannot be determined
 -  Let the school ages of Neelam and Shaan be 5X and 6X years respectively. Then,
1 x 5X 3  

 

1 x 6X 2  

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