A man buys 5 horses and 7 oxen for Rs 5850. He sells the horses at a profit of 10% and oxen at a profit of 16% and his whole gain is Rs 711. What price does he pay for a horse? Options: A . &nbspRs 750 B . &nbspRs 800 C . &nbspRs 850 D . &nbspRs 850

Answer: Option A Let's assume that the cost price of each horse is x, and the cost price of each ox is y. From the given information, we have the following equations: 5x + 7y = 5850 (equation 1) 0.1 * 5x + 0.16 * 7y = 711 (equation 2) Simplifying equation 2, we get:0.5x + 1.12y = 711 (equation 3) Multiplying equation 1 by 0.5, we get:2.5x + 3.5y = 2925 (equation 4) Subtracting equation 3 from equation 4, we get:2x + 2.38y = 1215 Solving for x, we get:x = 750 Therefore, the cost price of each horse is Rs 750. Formulas: Profit = Selling price - Cost price Percentage profit = (Profit / Cost price) * 100 Key Points: To solve the problem, we need to use the formula for profit and the formula for percentage profit. We can assume the cost price of each horse and each ox, and then use the given information to form equations and solve for the unknowns. In this case, we assumed that the cost price of each horse is x, and the cost price of each ox is y, and used the given information to form equations and solve for x. If you think the solution is wrong then please provide your own solution below in the comments section .

A man buys 5 horses and 7 oxen for Rs 5850. He sells the horses at a profit of 1

Question

A man buys 5 horses and 7 oxen for Rs 5850. He sells the horses at a profit of 10% and oxen at a profit of 16% and his whole gain is Rs 711. What price does he pay for a horse?

Options:

A . Rs 750

B . Rs 800

C . Rs 850

D . Rs 850

Answer: Option A
Let's assume that the cost price of each horse is x, and the cost price of each ox is y.
From the given information, we have the following equations:

5x + 7y = 5850 (equation 1)
0.1 * 5x + 0.16 * 7y = 711 (equation 2)

Simplifying equation 2, we get:0.5x + 1.12y = 711 (equation 3)
Multiplying equation 1 by 0.5, we get:2.5x + 3.5y = 2925 (equation 4)
Subtracting equation 3 from equation 4, we get:2x + 2.38y = 1215
Solving for x, we get:x = 750
Therefore, the cost price of each horse is Rs 750.
Formulas:

Profit = Selling price - Cost price
Percentage profit = (Profit / Cost price) * 100

Key Points:

To solve the problem, we need to use the formula for profit and the formula for percentage profit.
We can assume the cost price of each horse and each ox, and then use the given information to form equations and solve for the unknowns.
In this case, we assumed that the cost price of each horse is x, and the cost price of each ox is y, and used the given information to form equations and solve for x.

If you think the solution is wrong then please provide your own solution below in the comments section .

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1 Comments

Dheeraj kr 2019-03-17 13:06:25

Let cost price of each horse
=
h

cost price of each cow
=
c

5
h
+
7
c
=
5850

â‹¯
(
1
)

5
h
Ã—
10
100
+
7
c
Ã—
16
100
=
711
â‡’
h
2
+
28
c
25
=
711
â‡’
25
h
+
56
c
=
35550

â‹¯
(
2
)

Solving
(
1
)
and
(
2
)
yields
c
=
300
and
h
=
750