-  Let son's age 2 years ago be X
Man's age 2 years ago = 6X
2 (X + 2 + 18) = (6X + 2 + 18)
4X = 20
X = 5
Their present ages are (6X + 2) and (X + 2),
i.e., 32 years and 7 years

Let us denote the present age of the man and his son by x and y respectively.

Then, two years ago, the age of the man was x-2 and the age of his son was y-2.

According to the question,

x-2 = 6(y-2)
⇒ x-2 = 6y-12
⇒ x = 6y-10

After 18 years, the age of the man will be x+18 and the age of his son will be y+18.

According to the question,

x+18 = 2(y+18)
⇒ x+18 = 2y+36
⇒ x = 2y+18

Substituting the value of x in the equation x = 6y-10, we get

6y-10 = 2y+18
⇒ 4y = 28
⇒ y = 7

Substituting the value of y in the equation x = 6y-10, we get

x = 6y-10
⇒ x = 6×7-10
⇒ x = 32

Hence, the present ages of the man and his son are 32 years and 7 years respectively.

Therefore, Option A. 32 years and 7 years is the correct answer.