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Question

Two cards are drawn together from a pack of 52 cards. The probability that one is a spade and one is a heart, is:

Options:
A .  \(\frac{3}{20}\)
B .  \(\frac{29}{34}\)
C .  \(\frac{47}{100}\)
D .  \(\frac{13}{102}\)
Answer: Option D

Let S be the sample space.


Then, n(S) = 52C2 =   \(\frac{(52\times51)}{(2\times1)}\) = 1326.


Let E = event of getting 1 spade and 1 heart.


So, n(E)  = number of ways of choosing 1 spade out of 13 and 1 heart out of 13


 = (13C1 x 13C1)


= (13 x 13)


= 169.


So, \(P(E) = \frac{n(E)}{n(S)}=\frac{169}{1326}=\frac{13}{102}.\)


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